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anonymous
 one year ago
1.Solve for p
3(p+q)=p
2.solve for b then find the value of b when a=3
4a=2b7
3. Solve for r
D=rt
4. Find the width of a rectangle with a perimeter of 90 and the length of 15
anonymous
 one year ago
1.Solve for p 3(p+q)=p 2.solve for b then find the value of b when a=3 4a=2b7 3. Solve for r D=rt 4. Find the width of a rectangle with a perimeter of 90 and the length of 15

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.01. 3pp=3q therefore p=(3/2)q 2. 2b7=4a therefore 2b=4a+7 therefore b=2a+7/2 in order to see how much is b when a=3, just plug in a=3, and we get b=2(3)+7/2=19/2 3. r=D/t 4. perimeter=2(length)+2(width) therefore 2width=perimeter2(length). Divide both sides by 2 and plug in numbers: width= 90/215=30

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you ππ»π
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