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anonymous

  • one year ago

The point (2, 3) is on the terminal side of angle θ, in standard position. What are the values of sine, cosine, and tangent of θ? Make sure to show all work.

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  1. anonymous
    • one year ago
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    @jeweaver145

  2. anonymous
    • one year ago
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    |dw:1442516732915:dw|

  3. anonymous
    • one year ago
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    so your first move would be to find the length of the hypotenuse and then use the trig identities to solve for the sin cos and tan!

  4. anonymous
    • one year ago
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    How do I do that?

  5. anonymous
    • one year ago
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    ok, to find the hypotenuse, you use the pythagorean theorem. you know how to do that?

  6. anonymous
    • one year ago
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    its \[c=\sqrt{a^2+b^2}\]

  7. anonymous
    • one year ago
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    |dw:1442517134981:dw|

  8. anonymous
    • one year ago
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    right, so you find c, which is the hypotenuse, by using a=3 and b-2 in that equation. Then you can use the trig in my picture to solve!

  9. anonymous
    • one year ago
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    it would be \[\pm \sqrt{13}\]

  10. anonymous
    • one year ago
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    |dw:1442518343430:dw| now do you know the opposite and adjacent of the angle (theta)?

  11. anonymous
    • one year ago
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    I do not :( How do I find that?

  12. anonymous
    • one year ago
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    |dw:1442518455593:dw|

  13. anonymous
    • one year ago
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    |dw:1442518522779:dw|

  14. anonymous
    • one year ago
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    So adjacent would be 2 and Opp would be 3?

  15. anonymous
    • one year ago
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    right! then use just use the equations in my first picture to solve it out!

  16. anonymous
    • one year ago
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    Absolutely! Can you now find the sin, cos, and tan? |dw:1442518693365:dw|

  17. anonymous
    • one year ago
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    what would the equation be?

  18. anonymous
    • one year ago
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    @jeweaver145 @mathway

  19. anonymous
    • one year ago
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    for example, sin(theta) would be opp/hyp=3/sqrt(14)

  20. anonymous
    • one year ago
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    I'm so confused :(

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