HELP MEDAL GIVEN!!! Question Down Below I v

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HELP MEDAL GIVEN!!! Question Down Below I v

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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The Quadratic Equation : \[2x^2 + 4x + 3 = 0\] I have done part a) and b) so part c question is : find the value of : \[\alpha^4 + \beta^4\]

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well \[\alpha^4 + \beta^4= (\alpha^2 + \beta^2)^2 - 2 \alpha^2 \beta^2\] so that is probably a start
so apply the same reasoning to deal with \[(\alpha^2 + \beta^2)^2\] so that it is in terms of \[\alpha + \beta\]
ok... so \[\alpha^2 + \beta^2 = (\alpha + \beta)^2 - 2\alpha \beta\] so calculate this and then substitute it
and in the original equation \[2\alpha^2 beat^2 = 2(\alpha \beta)^2\]
so for that I got the answer = 1
well that makes sense so you have \[(1)^2 - 2(\alpha \beta)^2\]
a medal and i will help
so, that equals = -7/2
that's it

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