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anonymous
 one year ago
HELP MEDAL GIVEN!!!
Question Down Below I
v
anonymous
 one year ago
HELP MEDAL GIVEN!!! Question Down Below I v

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The Quadratic Equation : \[2x^2 + 4x + 3 = 0\] I have done part a) and b) so part c question is : find the value of : \[\alpha^4 + \beta^4\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Nnesha @nincompoop @paki

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Luigi0210 @campbell_st

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2well \[\alpha^4 + \beta^4= (\alpha^2 + \beta^2)^2  2 \alpha^2 \beta^2\] so that is probably a start

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2so apply the same reasoning to deal with \[(\alpha^2 + \beta^2)^2\] so that it is in terms of \[\alpha + \beta\]

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2ok... so \[\alpha^2 + \beta^2 = (\alpha + \beta)^2  2\alpha \beta\] so calculate this and then substitute it

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2and in the original equation \[2\alpha^2 beat^2 = 2(\alpha \beta)^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so for that I got the answer = 1

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.2well that makes sense so you have \[(1)^2  2(\alpha \beta)^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0a medal and i will help

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so, that equals = 7/2
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