anonymous
  • anonymous
HELP MEDAL GIVEN!!! Question Down Below I v
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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anonymous
  • anonymous
The Quadratic Equation : \[2x^2 + 4x + 3 = 0\] I have done part a) and b) so part c question is : find the value of : \[\alpha^4 + \beta^4\]
anonymous
  • anonymous
@Nnesha @nincompoop @paki
anonymous
  • anonymous
@Luigi0210 @campbell_st

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campbell_st
  • campbell_st
well \[\alpha^4 + \beta^4= (\alpha^2 + \beta^2)^2 - 2 \alpha^2 \beta^2\] so that is probably a start
campbell_st
  • campbell_st
so apply the same reasoning to deal with \[(\alpha^2 + \beta^2)^2\] so that it is in terms of \[\alpha + \beta\]
campbell_st
  • campbell_st
ok... so \[\alpha^2 + \beta^2 = (\alpha + \beta)^2 - 2\alpha \beta\] so calculate this and then substitute it
campbell_st
  • campbell_st
and in the original equation \[2\alpha^2 beat^2 = 2(\alpha \beta)^2\]
anonymous
  • anonymous
so for that I got the answer = 1
campbell_st
  • campbell_st
well that makes sense so you have \[(1)^2 - 2(\alpha \beta)^2\]
anonymous
  • anonymous
a medal and i will help
anonymous
  • anonymous
so, that equals = -7/2
campbell_st
  • campbell_st
that's it

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