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Meehan98
 one year ago
A die is rolled twice. What is the probability of getting either a multiple of 3 on the first roll or a total of 8 for both rolls?
Meehan98
 one year ago
A die is rolled twice. What is the probability of getting either a multiple of 3 on the first roll or a total of 8 for both rolls?

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Meehan98
 one year ago
Best ResponseYou've already chosen the best response.1This is what I have so far: P(multiple of 3)=2/6 P (sum of 8)=6/16 Then, you add both of them to get 31/48, but this is incorrect.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wait I am not sure. Lemme think about it more

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What is the correct answer?

Meehan98
 one year ago
Best ResponseYou've already chosen the best response.1Well, these are the possible answers: 5/12 7/18 13/180 4/9

Meehan98
 one year ago
Best ResponseYou've already chosen the best response.1Yea, I got 25/108 so something's off; I just don't know what?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh, I read the question wrong. I thought it was probability of of getting multiple of 3 and getting a roll of 8 on both rolls.

Meehan98
 one year ago
Best ResponseYou've already chosen the best response.1So, I keep getting different answers each time I complete the problem. Now I got 8/9 because I added 2/6 + 5/6=7/6 and subtracted that from 10/36 according to the Inclusive events formula P ( A or B)= P(A) +P(B)P(A and B)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Its been a while. Gimme a few more minutes.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Got it. P(A)+P(B) P( A and B)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0For the multiple of 3 only three and six work.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.02,6 3,5 4,4 5,3 6,2 All this would add up to 8. Now we would use independent event formula by multiplying probability by probability The chance of getting any of those number is

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Equation bugged out.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Continued from 2 post above is \[\frac{ 5 }{ 6 }\] Chances for second dice would be 1/6 since you only need one number to make it 8. So \[\frac{ 5 }{ 6 } \times \frac{ 1 }{ 6 }=\frac{ 25 }{ }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(5/36+2/6) P(A and B) P(A and B) would be \[\frac{ 2 }{ 6 } \times \frac{ 1 }{ 6 }=2/36\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You could have wait. If it was a timed test, you should have studied _

Meehan98
 one year ago
Best ResponseYou've already chosen the best response.1I understand how you have received all of these besides one part. (5/36+2/6)  P (A and B) I know that it's 2/6 from the multiple of 3 but where did you get 1/6? because I thought that P(total of 8 for both rolls)=5/36.

Meehan98
 one year ago
Best ResponseYou've already chosen the best response.1It wasn't a test, it's a lesson that I didn't fully grasp. I apologize for not responding sooner; I was working out the problem again. You've been wonderful help. Thank you!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ah, I see. I was eating dinner, so sorry for the delay. P(A+B) is the probability for both event (A&B) to happen. A is the probability for it to be multiples of 3 which is 2/6 B is probability to add up to 8. If you rolled 3 on first dice, then second dice would need to be 5 to make it 8. If you rolled 6 on first dice, second dice would need to be 2 to make it 8. Because even if you were lucky to roll a 3 on first dice, you would need 5 on second dice. That would be a 1/6 chance so 2/6 x 1/6

Meehan98
 one year ago
Best ResponseYou've already chosen the best response.1Ah, you're wonderful at explaining things! Thank you so much!!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks for the feedback and nice job attempting it. Good luck on the rest!
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