A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

I'm so confused can someone help?? The driver of a pickup truck going 120 km/h applies the brakes, giving the truck a uniform deceleration of 5.00 m/s2 while it travels 35.0 m. How much time has elapsed?

  • This Question is Closed
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1442519392779:dw| this is about as far as I could get...I have no idea where to go with this

  2. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Reverse the acceleration formula

  3. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    a=v/t?

  4. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Wait nvm completely read that wrong, sorry dislexia. But can't help out, not there yet

  5. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh...lol thanks for trying :)

  6. YumYum247
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Given: Vi = 120Km/hr, a = 5m/sec^2, dh = 35m Variables not given: Vf Required: t USe the d= Vi X t + 1/2(a X t^2) and solve for "t"

  7. YumYum247
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1442520996689:dw|

  8. YumYum247
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1442521175552:dw|

  9. YumYum247
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1442521263494:dw|

  10. YumYum247
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1442521386768:dw|

  11. YumYum247
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1442521480339:dw|

  12. YumYum247
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1442521549547:dw|

  13. YumYum247
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1442521649160:dw|

  14. YumYum247
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1442521737159:dw|

  15. YumYum247
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1442521815577:dw|

  16. YumYum247
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1442521871193:dw|

  17. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    can you slow down and explain some of these? I don't really understand. like in the 2nd photo where are you getting the 5 you're diving by?

  18. YumYum247
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1442521915394:dw|

  19. YumYum247
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1442522049419:dw|

  20. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    can you please explain what you are doing....

  21. YumYum247
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    hold up i'm a lil stuck...LOL

  22. YumYum247
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    oh i got it....i didn't quite read "deceleration...a = -5m/sec^2

  23. YumYum247
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1442522102414:dw| Restart!!!! :"D

  24. YumYum247
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    there should have been a negative sign in front of the -2.5 that i forgot to put,....

  25. YumYum247
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    i'll explain just hold on....

  26. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    lol maybe try using the equation tool instead of the drawing tool

  27. YumYum247
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    cuz i can....|dw:1442522842144:dw|

  28. YumYum247
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1442522970389:dw|

  29. YumYum247
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1442523113354:dw|

  30. YumYum247
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1442523188249:dw|

  31. YumYum247
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1442523291101:dw|

  32. YumYum247
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1442523343336:dw|

  33. YumYum247
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    |dw:1442523472986:dw|

  34. YumYum247
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    t= -33.3 + 27.54/-5 t= -5.76/-5 t=1.152sec

  35. YumYum247
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    i'm out!!!!

  36. YumYum247
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    Always remember this trick....identify your variables... see what's given to you and what isn't and what is required..... in this case. They gave us the acceleration, initial velocity and horizontal distance. but they didn't tell us the final velocity and asked you to find the time...this is where you need to use a little trick, use the formula for which the variable isn't given...

  37. YumYum247
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    in this case, fnal velocity.

  38. YumYum247
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    1 Attachment
  39. YumYum247
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 2

    and solve for the "T". you should get a quadratics expression.....t = m/sec^2T^2 + m/secT -horizontal distance(35m) use the quadratics formula to solve for time....