anonymous
  • anonymous
I'm so confused can someone help?? The driver of a pickup truck going 120 km/h applies the brakes, giving the truck a uniform deceleration of 5.00 m/s2 while it travels 35.0 m. How much time has elapsed?
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
|dw:1442519392779:dw| this is about as far as I could get...I have no idea where to go with this
anonymous
  • anonymous
Reverse the acceleration formula
anonymous
  • anonymous
a=v/t?

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anonymous
  • anonymous
Wait nvm completely read that wrong, sorry dislexia. But can't help out, not there yet
anonymous
  • anonymous
oh...lol thanks for trying :)
YumYum247
  • YumYum247
Given: Vi = 120Km/hr, a = 5m/sec^2, dh = 35m Variables not given: Vf Required: t USe the d= Vi X t + 1/2(a X t^2) and solve for "t"
YumYum247
  • YumYum247
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YumYum247
  • YumYum247
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YumYum247
  • YumYum247
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YumYum247
  • YumYum247
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YumYum247
  • YumYum247
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YumYum247
  • YumYum247
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YumYum247
  • YumYum247
|dw:1442521649160:dw|
YumYum247
  • YumYum247
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YumYum247
  • YumYum247
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YumYum247
  • YumYum247
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anonymous
  • anonymous
can you slow down and explain some of these? I don't really understand. like in the 2nd photo where are you getting the 5 you're diving by?
YumYum247
  • YumYum247
|dw:1442521915394:dw|
YumYum247
  • YumYum247
|dw:1442522049419:dw|
anonymous
  • anonymous
can you please explain what you are doing....
YumYum247
  • YumYum247
hold up i'm a lil stuck...LOL
YumYum247
  • YumYum247
oh i got it....i didn't quite read "deceleration...a = -5m/sec^2
YumYum247
  • YumYum247
|dw:1442522102414:dw| Restart!!!! :"D
YumYum247
  • YumYum247
there should have been a negative sign in front of the -2.5 that i forgot to put,....
YumYum247
  • YumYum247
i'll explain just hold on....
anonymous
  • anonymous
lol maybe try using the equation tool instead of the drawing tool
YumYum247
  • YumYum247
cuz i can....|dw:1442522842144:dw|
YumYum247
  • YumYum247
|dw:1442522970389:dw|
YumYum247
  • YumYum247
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YumYum247
  • YumYum247
|dw:1442523188249:dw|
YumYum247
  • YumYum247
|dw:1442523291101:dw|
YumYum247
  • YumYum247
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YumYum247
  • YumYum247
|dw:1442523472986:dw|
YumYum247
  • YumYum247
t= -33.3 + 27.54/-5 t= -5.76/-5 t=1.152sec
YumYum247
  • YumYum247
i'm out!!!!
YumYum247
  • YumYum247
Always remember this trick....identify your variables... see what's given to you and what isn't and what is required..... in this case. They gave us the acceleration, initial velocity and horizontal distance. but they didn't tell us the final velocity and asked you to find the time...this is where you need to use a little trick, use the formula for which the variable isn't given...
YumYum247
  • YumYum247
in this case, fnal velocity.
YumYum247
  • YumYum247
1 Attachment
YumYum247
  • YumYum247
and solve for the "T". you should get a quadratics expression.....t = m/sec^2T^2 + m/secT -horizontal distance(35m) use the quadratics formula to solve for time....
YumYum247
  • YumYum247
get it? O_O
YumYum247
  • YumYum247
ii'm getting late. do some question and hope for the best!!! :"D later!!!!!!!
anonymous
  • anonymous
yes i think i got it now sorry my internet froze xP also that table is super helpful. my textbook doesn't have that O.o

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