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|dw:1442519392779:dw| this is about as far as I could get...I have no idea where to go with this
Reverse the acceleration formula
Wait nvm completely read that wrong, sorry dislexia. But can't help out, not there yet
oh...lol thanks for trying :)
Given: Vi = 120Km/hr, a = 5m/sec^2, dh = 35m Variables not given: Vf Required: t USe the d= Vi X t + 1/2(a X t^2) and solve for "t"
can you slow down and explain some of these? I don't really understand. like in the 2nd photo where are you getting the 5 you're diving by?
can you please explain what you are doing....
hold up i'm a lil stuck...LOL
oh i got it....i didn't quite read "deceleration...a = -5m/sec^2
|dw:1442522102414:dw| Restart!!!! :"D
there should have been a negative sign in front of the -2.5 that i forgot to put,....
i'll explain just hold on....
lol maybe try using the equation tool instead of the drawing tool
cuz i can....|dw:1442522842144:dw|
t= -33.3 + 27.54/-5 t= -5.76/-5 t=1.152sec
Always remember this trick....identify your variables... see what's given to you and what isn't and what is required..... in this case. They gave us the acceleration, initial velocity and horizontal distance. but they didn't tell us the final velocity and asked you to find the time...this is where you need to use a little trick, use the formula for which the variable isn't given...
in this case, fnal velocity.
and solve for the "T". you should get a quadratics expression.....t = m/sec^2T^2 + m/secT -horizontal distance(35m) use the quadratics formula to solve for time....
get it? O_O
ii'm getting late. do some question and hope for the best!!! :"D later!!!!!!!
yes i think i got it now sorry my internet froze xP also that table is super helpful. my textbook doesn't have that O.o