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anonymous
 one year ago
Express as a single logarithm.
log6496 – log62
I know logs pretty well but I don't know how to express 2 logs as a single log, can someone please help??
anonymous
 one year ago
Express as a single logarithm. log6496 – log62 I know logs pretty well but I don't know how to express 2 logs as a single log, can someone please help??

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I meant log base 6 of 496  log base 6 of 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\log_{6} 496\log_{6} 2=\log_{6} \frac{ 496 }{ 2 }=\log_{6} 248\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That's what I thought thank you! What about, log base 5 of 50 + log base 5 of 2.5?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know it has to equal something in the final answer and that confuses me

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0quotient rule\[\large\rm log_b x  \log_b y = \log_b \frac{ x }{ y}\] to condense you can change subtraction to division product rule \[\large\rm log_b x + \log_b y = \log_b( x \times y )\] addition > multiplication power rule \[\large\rm log_b x^y = y \log_b x\] you should familiar with these

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0there is a plus sign so which property you should apply ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the product property

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I am doing a test review and all of the multiple choice answers for the question equal something, like one answer is, log base 5 of 125=3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How do you find what it equals?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0log base 5 of 50 + log base 5 of 2.5 for this question ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge\rm log_5 50+ \log_5 2.5\] is this ur question ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0there isn't an equal sign..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0These are the possible answers: \[\log_{5}125=3 \] \[\log_{5}112.5=2.93 \] \[\log_{5}112.5=22.5 \] \[\log_{5}125=625 \]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0alright then you have to apply the `change of base` formula \[\huge\rm log_b a= \frac{ \log a }{ \log b }\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge\rm log_5 50+ \log_5 2.5\] first) how would you write this in single log form b applying product property ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0yes right now use change of base formula

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How do I know what to change the base to?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0base would stay the same hmm what do you mean ? o.O here is an example \[\log_2 3 =\frac{ \log(3) }{ \log(2) }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh okay! I was looking at my notes and I read the equation wrong!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0soooo is the answer \[\log_{5}125=3 \]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0if log_5 (125) is equal to 3 then yes did you use the formula ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0how would you use `change of base formula` for \[\large\rm \log_5 125\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ \log(125) }{ \log(5) }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Awesome! This makes sense now! Thank you so much! You are very smart

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0glad to hear that & thanks & good job! good luck !
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