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|dw:1442524295814:dw|

Maybe even exponentials, like exp(-x) or something?

I'm thinking ln or log function, not sure though

that's what the graph I have looks like, so I'd say so

With logarithms you wouldn't get a horizontal asymptote...

After substituting (0, 0) and (1, 2), I got this:

First, try (0, 0): \(0=\dfrac{0+b}{0+d}\), so \(\dfrac{b}{d}=0\), which means c=0.

thank you!! that actually helped a lot :)