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alexrobin13
 one year ago
Find the equation of the function. (please explain so I understand)
alexrobin13
 one year ago
Find the equation of the function. (please explain so I understand)

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alexrobin13
 one year ago
Best ResponseYou've already chosen the best response.0dw:1442524295814:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hmm. A tricky one. I think I can help you, if you help me help you :) Based on whatever you've been doing at school, can you make a guess about what sort of function we might need to use? I can think of lots of examples, like sqrt(), tan(), 1/x, and so on. Any guesses?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Maybe even exponentials, like exp(x) or something?

alexrobin13
 one year ago
Best ResponseYou've already chosen the best response.0I'm thinking ln or log function, not sure though

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, that's certainly sounds possible. Just to check though, is y=4 an asymptote? (i.e. the line gets closer and closer to 4 but doesn't touch it?)

alexrobin13
 one year ago
Best ResponseYou've already chosen the best response.0that's what the graph I have looks like, so I'd say so

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It looks like a rational function: \(y=\dfrac{ax+b}{cx+d}\). If it is, you can find out the values of a, b, c and d by examining the graph: begin with the horizontal asymptote. Because that is y=4, this means a/c=4, so take a=4 and c=1. All you need to do now is substituting (0,0) and (1,2) to find the values of b and d...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0With logarithms you wouldn't get a horizontal asymptote...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0After substituting (0, 0) and (1, 2), I got this:

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0First, try (0, 0): \(0=\dfrac{0+b}{0+d}\), so \(\dfrac{b}{d}=0\), which means c=0.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Now try (1, 2): \(2=\dfrac{4 \cdot 1}{1+d}\), so \(1+d=\dfrac{4}{2}=2\), which means: \(d=1\). All in all we have: \(y=\dfrac{4x}{x+1}\). There could be othewr formulas, involving the exponential function.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Like \(y=4a\cdot e^{bx}\). Again, the values of a and b can be found by substituting (0, 0) and (1, 2).

alexrobin13
 one year ago
Best ResponseYou've already chosen the best response.0thank you!! that actually helped a lot :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0YW! When I try the exponential function, I get (after substituting the points (0, 0) and (1, 2)): \(y=44e^{x \ln 2}\) See image. It matches the specs, maybe even better, because the graph rises faster to the asymptote y=4. Looks more like your drawing imo.
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