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YumYum247

  • one year ago

Someone please help me!!!

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  1. YumYum247
    • one year ago
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    A 60 Kg person gets on an elevaator in the Mclennan Physics labs at the university of Toronto. Naturally, there's a scale (measuring Newtons) on the floor, The person steps on the scale and presses "UP". The scale reads 700N (UP). Determine the acceleration of the elevator. Draw a free body diagram.

  2. YumYum247
    • one year ago
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    |dw:1442526744201:dw|

  3. YumYum247
    • one year ago
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    The natural force pushing down o nthe person is = Fn = 60Kg (9.80m/sec^2) = 588N(Down)

  4. YumYum247
    • one year ago
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    @IrishBoy123 Please help ME!!

  5. YumYum247
    • one year ago
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    Fn = 588(down) Fs = 700N (UP) Fs = m.a - m.g Fs = |dw:1442527123799:dw|

  6. YumYum247
    • one year ago
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    @Astrophysics HELLP!!! PLEASE!!!

  7. YumYum247
    • one year ago
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    am i even remotely close to the right track?

  8. Astrophysics
    • one year ago
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    :3

  9. YumYum247
    • one year ago
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    :D

  10. YumYum247
    • one year ago
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    true.

  11. Astrophysics
    • one year ago
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    |dw:1442528711236:dw| here's the thing, when the elevator is going up, the acceleration of elevator = acceleration of student

  12. Astrophysics
    • one year ago
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    \[F_{net}=T+W\] so these are the only forces acting on the student

  13. YumYum247
    • one year ago
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    his weight and what...T?

  14. Astrophysics
    • one year ago
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    Tension (scale)

  15. YumYum247
    • one year ago
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    ok is the tension given to us or nah? no right.

  16. Astrophysics
    • one year ago
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    It is, 700N :)

  17. YumYum247
    • one year ago
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    ok....:D

  18. Astrophysics
    • one year ago
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    As the student is rising the scale reads 700N

  19. YumYum247
    • one year ago
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    so his acceleration is 700N X 60kg?

  20. Astrophysics
    • one year ago
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    \[ma = T+mg \implies a = \frac{ T+mg }{ m }\]

  21. YumYum247
    • one year ago
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    |dw:1442528962628:dw|

  22. Astrophysics
    • one year ago
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    The 60 kg is mass not weight, weight is a force

  23. Astrophysics
    • one year ago
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    W = mg

  24. YumYum247
    • one year ago
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    OMG I'm Sorry :(

  25. Astrophysics
    • one year ago
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    xD

  26. YumYum247
    • one year ago
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    could you please deinfe Tension for me please!!!

  27. Astrophysics
    • one year ago
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    Tension is the applied force here, which be exerted by pushing or pulling the object, but since the elevator is going up, it is being pulled so that is the applied force here (Tension) which is opposing weight

  28. YumYum247
    • one year ago
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    Oh ok cuz i know it by F sub applied, i didn't know it's tension too..

  29. Astrophysics
    • one year ago
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    Applied force = tension, it doesn't matter :P, people often confuse it

  30. Astrophysics
    • one year ago
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    Different notations with same meanings pretty much

  31. YumYum247
    • one year ago
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    ok Thanks...just one last thing....could you please name the follow...

  32. YumYum247
    • one year ago
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    m.a = ? M.g = ? T = Fapplied

  33. Astrophysics
    • one year ago
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    What do you mean?

  34. YumYum247
    • one year ago
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    does net force = m.a right?

  35. Astrophysics
    • one year ago
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    Weight = mg Newton's second law = ma, in the case it's the net force

  36. Astrophysics
    • one year ago
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    F=ma*

  37. Astrophysics
    • one year ago
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    Yes

  38. YumYum247
    • one year ago
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    I got it.... Thanks and I LOVE YOU SHOOOOOO MUCH!!!! <3

  39. Astrophysics
    • one year ago
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    By the way, there is a trick question with elevators you may run into

  40. YumYum247
    • one year ago
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    please tell me.....:")

  41. Astrophysics
    • one year ago
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    If you ever have a question that says, the elevator is moving up/down what ever at a CONSTANT VELOCITY that implies acceleration = 0

  42. YumYum247
    • one year ago
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    OOOOOOOOOooooooooooooooooooooooooooo!!!! Thanks.....:")

  43. Astrophysics
    • one year ago
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    Yw :) teachers often like to trick students with stuff life that, you have to remember your kinetmatics during those questions

  44. YumYum247
    • one year ago
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    i've mastered my kinematics!!!

  45. YumYum247
    • one year ago
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    :D

  46. YumYum247
    • one year ago
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    Anyways plz don't go, i may need your help....thanks :")

  47. Astrophysics
    • one year ago
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    :)

  48. YumYum247
    • one year ago
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    OH btw Weight = Normal Force right??????????

  49. Astrophysics
    • one year ago
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    Well...if there is a surface, and then the perpendicular force would be same as weight.

  50. YumYum247
    • one year ago
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    ok i'll take that as a yes!!!!!

  51. Astrophysics
    • one year ago
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    |dw:1442529792131:dw|

  52. Astrophysics
    • one year ago
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    But for the elevator, there is no normal force when it's moving

  53. YumYum247
    • one year ago
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    ok thanks :")

  54. YumYum247
    • one year ago
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    |dw:1442530093066:dw|

  55. YumYum247
    • one year ago
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    does it look ok ?????

  56. Astrophysics
    • one year ago
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    Note the direction of the forces

  57. YumYum247
    • one year ago
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    the 60kg will cancel out right?????

  58. YumYum247
    • one year ago
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    ok sorry!! :)

  59. Astrophysics
    • one year ago
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    \[\vec F _{net}= \vec T + \vec W \implies m \vec a = \vec T +m \vec g \implies \vec a = \frac{ \vec T +m \vec g }{ m }\]

  60. Astrophysics
    • one year ago
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    g = - 9.81 m/s^2

  61. YumYum247
    • one year ago
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    oh really?????

  62. YumYum247
    • one year ago
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    g = -9.81....ok thanks....but 60kg will cancel out right??????

  63. Astrophysics
    • one year ago
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    Why?

  64. Astrophysics
    • one year ago
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    It can be \[\vec a = \frac{ \vec T }{ m }+ \vec g\]

  65. YumYum247
    • one year ago
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    because kg.m/sec^2 = N if i'll have 2N in the numerator and kg in the denominator...

  66. YumYum247
    • one year ago
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    ok that still doesn't make things easier to solve :(

  67. YumYum247
    • one year ago
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    |dw:1442530594548:dw|

  68. YumYum247
    • one year ago
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    |dw:1442530658933:dw|

  69. YumYum247
    • one year ago
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    |dw:1442530740704:dw|

  70. YumYum247
    • one year ago
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    |dw:1442530801983:dw|

  71. YumYum247
    • one year ago
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    i got it!!! :"D

  72. YumYum247
    • one year ago
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    @Astrophysics I Love you dear!!!! :") :D

  73. YumYum247
    • one year ago
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    Thanks a mol.

  74. Astrophysics
    • one year ago
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    :)

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