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anonymous
 one year ago
if f(x) = x^2 3x and g(x) = (√x)1, then f(g(x)) =
anonymous
 one year ago
if f(x) = x^2 3x and g(x) = (√x)1, then f(g(x)) =

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Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0f(g(x)) can be written as f(sqrt{x}1) so replace x with g(x) function into f(x) equation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i did but i still dont get it unfortunatey

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge\rm f(x)=x^23x\] replace x with sqrt{X} 1

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0what did you get ? can i see ur work plz

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i got ((√x)1)^2  3((√)1)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge\rm (\sqrt{x}1)^23(\sqrt{x}1)\] distribute 2nd parentheses by 3 and apply foil method for (sqrt{x}1)^2

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0do you know how to distribute ?3(Sqrt{X}1) ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no i dont unfortunately. I dont know how to distribute the 3 to the sqaure roots or how to do the first set of parenthesis

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0apply distributive property distribute parentheses by outside number/ \[\huge\rm \color{reD}{a}(b+c) =\color{red}{a} ·b +\color{reD}{a}·c =\color{ReD}{a}b +\color{ReD}{a}c\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\[3(\sqrt{x}1)\] multiply 3 times sqrt{x} and then 3 times 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh okay. I got this for the second set of parenthesis: 3√x+3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how do i foil square roots?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0yes right now foil (sqrt{x} 1)^2 is same as \[\huge\rm (\sqrt{x}1)(\sqrt{x}1)\]dw:1442527466021:dw multiply 2nd parentheses by by first term sqrt{x} and then by 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i ended up getting : √2x √x √x +1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i mean: √x^2  √2x +1

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\[\sqrt{2x}\]isn't right

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0dw:1442528022410:dw it would 2sqrt{x}

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0just like variables when we combine them we should coefficient add/subtract their coefficient

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so it isnt √x^2  √2x +1 ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0just like variables when we combine them we should coefficient add/subtract their coefficient so \[\sqrt{x}\sqrt{x}=2\sqrt{x}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0for the first set of parenthesis

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh okay i see. so is it: √x^2  2√x +1

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0yes right now square root can cancel out the square so sqrt{x^2} = ??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay so it would be x  √2x +1 3√x +3???

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0yes right \[\huge\rm x2\sqrt{x}+13\sqrt{x}+3\] now combine like terms

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so it would be x5√x+4?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you very much for your help :)
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