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anonymous

  • one year ago

if f(x) = x^2 -3x and g(x) = (√x)-1, then f(g(x)) =

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  1. Nnesha
    • one year ago
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    f(g(x)) can be written as f(sqrt{x}-1) so replace x with g(x) function into f(x) equation

  2. anonymous
    • one year ago
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    i did but i still dont get it unfortunatey

  3. Nnesha
    • one year ago
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    \[\huge\rm f(x)=x^2-3x\] replace x with sqrt{X} -1

  4. Nnesha
    • one year ago
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    what did you get ? can i see ur work plz

  5. anonymous
    • one year ago
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    i got ((√x)-1)^2 - 3((√)-1)

  6. Nnesha
    • one year ago
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    \[\huge\rm (\sqrt{x}-1)^2-3(\sqrt{x}-1)\] distribute 2nd parentheses by -3 and apply foil method for (sqrt{x}-1)^2

  7. Nnesha
    • one year ago
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    do you know how to distribute ?-3(Sqrt{X}-1) ?

  8. anonymous
    • one year ago
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    no i dont unfortunately. I dont know how to distribute the -3 to the sqaure roots or how to do the first set of parenthesis

  9. Nnesha
    • one year ago
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    apply distributive property distribute parentheses by outside number/ \[\huge\rm \color{reD}{a}(b+c) =\color{red}{a} ·b +\color{reD}{a}·c =\color{ReD}{a}b +\color{ReD}{a}c\]

  10. Nnesha
    • one year ago
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    \[-3(\sqrt{x}-1)\] multiply -3 times sqrt{x} and then -3 times -1

  11. anonymous
    • one year ago
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    oh okay. I got this for the second set of parenthesis: -3√x+3

  12. anonymous
    • one year ago
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    how do i foil square roots?

  13. Nnesha
    • one year ago
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    yes right now foil (sqrt{x} -1)^2 is same as \[\huge\rm (\sqrt{x}-1)(\sqrt{x}-1)\]|dw:1442527466021:dw| multiply 2nd parentheses by by first term sqrt{x} and then by -1

  14. anonymous
    • one year ago
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    i ended up getting : √2x -√x -√x +1

  15. anonymous
    • one year ago
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    i mean: √x^2 - √2x +1

  16. Nnesha
    • one year ago
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    \[\sqrt{2x}\]isn't right

  17. Nnesha
    • one year ago
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    |dw:1442528022410:dw| it would -2sqrt{x}

  18. Nnesha
    • one year ago
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    just like variables when we combine them we should coefficient add/subtract their coefficient

  19. anonymous
    • one year ago
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    so it isnt √x^2 - √2x +1 ?

  20. Nnesha
    • one year ago
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    just like variables when we combine them we should coefficient add/subtract their coefficient so \[-\sqrt{x}-\sqrt{x}=-2\sqrt{x}\]

  21. anonymous
    • one year ago
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    for the first set of parenthesis

  22. Nnesha
    • one year ago
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    2nd term isn't right

  23. anonymous
    • one year ago
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    oh okay i see. so is it: √x^2 - 2√x +1

  24. Nnesha
    • one year ago
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    yes right now square root can cancel out the square so sqrt{x^2} = ??

  25. anonymous
    • one year ago
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    okay so it would be x - √2x +1 -3√x +3???

  26. Nnesha
    • one year ago
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    yes right \[\huge\rm x-2\sqrt{x}+1-3\sqrt{x}+3\] now combine like terms

  27. anonymous
    • one year ago
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    so it would be x-5√x+4?

  28. Nnesha
    • one year ago
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    yes looks right!

  29. anonymous
    • one year ago
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    thank you very much for your help :)

  30. Nnesha
    • one year ago
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    yw :=)

  31. Nnesha
    • one year ago
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    did a great job!

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