anonymous
  • anonymous
WILL FAN AND MEDAL PLEASE HELP
Chemistry
  • Stacey Warren - Expert brainly.com
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
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anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
@ChiefArnav @shamallamadingdong @dan815
anonymous
  • anonymous
@Nnesha @Cowboy17 @whpalmer4

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More answers

anonymous
  • anonymous
@angrybadger.exe @ariclifton @BloomLocke367 @brennanfunk
anonymous
  • anonymous
@Bossvideogamer21 @clamin @caliboy08
anonymous
  • anonymous
@CountryBoy15 @cheesymcdouble @DullJackel09
anonymous
  • anonymous
@Daniellelovee @diamondboy @Dragon123mama
diamondboy
  • diamondboy
Hi
diamondboy
  • diamondboy
Do u understand what u are asked and how far have u gone?
anonymous
  • anonymous
Hello
anonymous
  • anonymous
Ok! This isn't so bad, it just requires doing one subtraction per molecule. So if we look at that first list, we have H-Cl, then H-F right? So what we do is we look up H and Cl in the chart and get the numbers: 2.2 for H and 3.16 for Cl. Now subtract the smaller number from the bigger number, 3.16-2.2 = 0.96 Do the same thing for H-F, look up the numbers, do the subtraction and you will get 1.8 (check it) Now we take these values which are the bond polarities of the molecules and compare them by plugging them in, H-Cl < H-F will be .96 < 1.8 which is a true statement, so this part is right. Keep going and compare all the bonds. It will be easier if you are familiar with periodic table trends especially at the top right section is usually where most of your atoms will be found when doing organic chemistry. http://www.chemhume.co.uk/ASCHEM/Unit%201/Ch3IMF/Images%203/electronegativity_values.jpg
anonymous
  • anonymous
Alright, I think B but could you tell me? If I get it wrong my gpa goes down and I'm locked out of my quiz @Woodward
diamondboy
  • diamondboy
ok
diamondboy
  • diamondboy
H-F is more electronegative than them all
diamondboy
  • diamondboy
can u guess what d first one is.....because electronegativity increases across d period from left to right
anonymous
  • anonymous
I have no clue, I just feel like B sounds right...
anonymous
  • anonymous
@Woodward is there another way you can explain?
diamondboy
  • diamondboy
So we said electronegativity increases from left to right on d period of d periodic table
diamondboy
  • diamondboy
having that in mind H-F is greater than H-O>H-Cl>HS
diamondboy
  • diamondboy
so what is your answer @WhatEven
anonymous
  • anonymous
C?
diamondboy
  • diamondboy
what is the meaning of this "<"
diamondboy
  • diamondboy
?
anonymous
  • anonymous
I thought less than but I'm soooooo confused now
diamondboy
  • diamondboy
ok relax...it means less than
diamondboy
  • diamondboy
the answer is the final option
diamondboy
  • diamondboy
so H-F
anonymous
  • anonymous
That was wrong ;-;
diamondboy
  • diamondboy
how?
anonymous
  • anonymous
It said "NO"
diamondboy
  • diamondboy
if < means less than then thats d answer but if it means greater than then B is the answer
diamondboy
  • diamondboy
do u still have one more try?
diamondboy
  • diamondboy
Please I am sorry...
anonymous
  • anonymous
No sorry it was my last one
anonymous
  • anonymous
I'll get it unlocked tomorrow though and tag you
diamondboy
  • diamondboy
would probably try too get an answer before tomorrow. Thanks
anonymous
  • anonymous
Can I still tag you tomorrow?
diamondboy
  • diamondboy
sure
anonymous
  • anonymous
thanks
diamondboy
  • diamondboy
Thank God :)

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