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anonymous

  • one year ago

rewrite the equation in slope-intercept form.

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  1. jdoe0001
    • one year ago
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    start at the beginning, and finish when done

  2. anonymous
    • one year ago
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    What is the equation?

  3. anonymous
    • one year ago
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    I don't know how to start it

  4. anonymous
    • one year ago
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    the equation is 4x + 5y = 15

  5. anonymous
    • one year ago
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    OKay so slope intercept form is Y=mx+b. The letter B is the Y intercept, this means the point in the graph where the line goes through Y. Got it so far?

  6. anonymous
    • one year ago
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    OK so you want to get Y by itself

  7. anonymous
    • one year ago
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    So if you want Y on one side of the equation by itself what do you do?

  8. jdoe0001
    • one year ago
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    yeap, solve \(\bf 4x + 5{\color{brown}{ y}} = 15\) for "y" see what you get

  9. anonymous
    • one year ago
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    @jdoe0001 You got it from here?

  10. jdoe0001
    • one year ago
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    well.. is too simple methinks, but I can keep an eye

  11. anonymous
    • one year ago
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    do I subtract 4x from the left side?

  12. anonymous
    • one year ago
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    so I did that and got: 5y = 15 -4x I think I'm suppose to divide 5 from all of the numbers & got: y = 3 -4/5x or y = 4/5x + 3 ????

  13. jdoe0001
    • one year ago
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    well yes, divide by 5 thus \(\bf 4x + 5y = 15\implies 5y=15-4x\implies y=\cfrac{-4x+15}{5} \\ \quad \\ y=\cfrac{-4}{5}x+\cfrac{\cancel{15}}{\cancel{5}}\implies y=-\cfrac{4}{5}x+3\impliedby \textit{slope-intercept form}\) you'd put the "x" part first on the right-hand-side

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