Help me Please!!!

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

1 Attachment
where are you stuck?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

I've attempted to do all three questions on my own, but can you please check my work??? For question A....this is what i wrote...|dw:1442537315350:dw|
The reaction force would be the same (1000N left) since the mass of both stones A and B is the same.... so whatever force stone A was travelling at received the same force back from stone B and that's why it immediately stopped.
b) Determine the action force on stone B and its acceleration... Ans) Since the mass of both stones is the same, the applied force on stone A transferred the same force to the stone B. And therefore and it accelerated stone B with the same velocity.
c) Determine the velocity of stone B as it loses contact with A. I'm not really sure about think one, please help me.....!!! :")
@Astrophysics please come rescue me from this PLEASE!!!
What is app?
You need to be more consistent with your notation
Oh applied?
yuss Faap = applied.
i meant Fapp = applied.
Ok cool, so make your own FBD and label it
ok i'll do that, i can't draw it here tho, it takes too long :(
but my answers make sense right..
I don't really know what you were doing
Please kindly see the question sheet i uploaded... :")
Don't worry about being right now, lets try to get a systematic approach to it
You need to understand the system before you start doing the math
yaah!! :D ok
|dw:1442538995633:dw|
So your first question is asking to find the acceleration of stone A and reaction force acting on it, |dw:1442539047977:dw|
yes.!
When we deal with Newton's laws we set vertical and horizontal forces separately
ok.
So what are the forces on the horizontal?
applied Force....
oh sorry...actio and reaction forces!!
Yes, exactly!
so there is a force being applied to stone A which is moving in the right...
and in contrary the force that applied that force also experiences a reaction force in the opposite direction.
i'm referring to stone A so far,
so whatever pushed the stone A also felt the same force back.
So as it touches the stone B on the horizontal axis, the reaction force from stone B will push back on stone A which will cause the stone A to immediately stop. while the Stone B carries the net force recevied from stone A.
Sort of, think about Newton's third law of motion
I think you're starting to understand it, just mess around and see what you get
yah but in the case, there is no friction and most importantly the mass of both stones is the same....so therefore the net force that stone A is travelling at transfers the same force to the next stone. IF the mass of both stones were different then some of the energy would be utlized on moving that object on the horizontal axis...
When you deal with the mass note that when they are together you have \[m= (m_A+m_B)\]
oh ok...so the moment they touch each other, the mass is combined? O_o
what about acceleration at that moment????
That's what you have to figure out :)
Yah that's why i'm here XD

Not the answer you are looking for?

Search for more explanations.

Ask your own question