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where are you stuck?
I've attempted to do all three questions on my own, but can you please check my work??? For question A....this is what i wrote...|dw:1442537315350:dw|
The reaction force would be the same (1000N left) since the mass of both stones A and B is the same.... so whatever force stone A was travelling at received the same force back from stone B and that's why it immediately stopped.
b) Determine the action force on stone B and its acceleration... Ans) Since the mass of both stones is the same, the applied force on stone A transferred the same force to the stone B. And therefore and it accelerated stone B with the same velocity.
c) Determine the velocity of stone B as it loses contact with A. I'm not really sure about think one, please help me.....!!! :")
@Astrophysics please come rescue me from this PLEASE!!!
What is app?
You need to be more consistent with your notation
yuss Faap = applied.
i meant Fapp = applied.
Ok cool, so make your own FBD and label it
ok i'll do that, i can't draw it here tho, it takes too long :(
but my answers make sense right..
I don't really know what you were doing
Please kindly see the question sheet i uploaded... :")
Don't worry about being right now, lets try to get a systematic approach to it
You need to understand the system before you start doing the math
yaah!! :D ok
So your first question is asking to find the acceleration of stone A and reaction force acting on it, |dw:1442539047977:dw|
When we deal with Newton's laws we set vertical and horizontal forces separately
So what are the forces on the horizontal?
oh sorry...actio and reaction forces!!
so there is a force being applied to stone A which is moving in the right...
and in contrary the force that applied that force also experiences a reaction force in the opposite direction.
i'm referring to stone A so far,
so whatever pushed the stone A also felt the same force back.
So as it touches the stone B on the horizontal axis, the reaction force from stone B will push back on stone A which will cause the stone A to immediately stop. while the Stone B carries the net force recevied from stone A.
Sort of, think about Newton's third law of motion
I think you're starting to understand it, just mess around and see what you get
yah but in the case, there is no friction and most importantly the mass of both stones is the same....so therefore the net force that stone A is travelling at transfers the same force to the next stone. IF the mass of both stones were different then some of the energy would be utlized on moving that object on the horizontal axis...
When you deal with the mass note that when they are together you have \[m= (m_A+m_B)\]
oh ok...so the moment they touch each other, the mass is combined? O_o
what about acceleration at that moment????
That's what you have to figure out :)
Yah that's why i'm here XD