Help me Please!!!

- YumYum247

Help me Please!!!

- Stacey Warren - Expert brainly.com

Hey! We 've verified this expert answer for you, click below to unlock the details :)

- jamiebookeater

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

- YumYum247

##### 1 Attachment

- YumYum247

@sweetburger

- IrishBoy123

where are you stuck?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- YumYum247

I've attempted to do all three questions on my own, but can you please check my work???
For question A....this is what i wrote...|dw:1442537315350:dw|

- YumYum247

The reaction force would be the same (1000N left) since the mass of both stones A and B is the same.... so whatever force stone A was travelling at received the same force back from stone B and that's why it immediately stopped.

- YumYum247

b) Determine the action force on stone B and its acceleration...
Ans) Since the mass of both stones is the same, the applied force on stone A transferred the same force to the stone B. And therefore and it accelerated stone B with the same velocity.

- YumYum247

c) Determine the velocity of stone B as it loses contact with A.
I'm not really sure about think one, please help me.....!!! :")

- YumYum247

@Astrophysics please come rescue me from this PLEASE!!!

- Astrophysics

What is app?

- Astrophysics

You need to be more consistent with your notation

- Astrophysics

Oh applied?

- YumYum247

yuss Faap = applied.

- YumYum247

i meant Fapp = applied.

- Astrophysics

Ok cool, so make your own FBD and label it

- YumYum247

ok i'll do that, i can't draw it here tho, it takes too long :(

- YumYum247

but my answers make sense right..

- Astrophysics

I don't really know what you were doing

- YumYum247

Please kindly see the question sheet i uploaded... :")

- Astrophysics

Don't worry about being right now, lets try to get a systematic approach to it

- Astrophysics

You need to understand the system before you start doing the math

- YumYum247

yaah!! :D ok

- Astrophysics

|dw:1442538995633:dw|

- Astrophysics

So your first question is asking to find the acceleration of stone A and reaction force acting on it, |dw:1442539047977:dw|

- YumYum247

yes.!

- Astrophysics

When we deal with Newton's laws we set vertical and horizontal forces separately

- YumYum247

ok.

- Astrophysics

So what are the forces on the horizontal?

- YumYum247

applied Force....

- YumYum247

oh sorry...actio and reaction forces!!

- Astrophysics

Yes, exactly!

- YumYum247

so there is a force being applied to stone A which is moving in the right...

- YumYum247

and in contrary the force that applied that force also experiences a reaction force in the opposite direction.

- YumYum247

i'm referring to stone A so far,

- YumYum247

so whatever pushed the stone A also felt the same force back.

- YumYum247

So as it touches the stone B on the horizontal axis, the reaction force from stone B will push back on stone A which will cause the stone A to immediately stop. while the Stone B carries the net force recevied from stone A.

- Astrophysics

Sort of, think about Newton's third law of motion

- Astrophysics

I think you're starting to understand it, just mess around and see what you get

- YumYum247

yah but in the case, there is no friction and most importantly the mass of both stones is the same....so therefore the net force that stone A is travelling at transfers the same force to the next stone. IF the mass of both stones were different then some of the energy would be utlized on moving that object on the horizontal axis...

- Astrophysics

When you deal with the mass note that when they are together you have \[m= (m_A+m_B)\]

- YumYum247

oh ok...so the moment they touch each other, the mass is combined? O_o

- YumYum247

what about acceleration at that moment????

- Astrophysics

That's what you have to figure out :)

- YumYum247

Yah that's why i'm here XD

Looking for something else?

Not the answer you are looking for? Search for more explanations.