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YumYum247

  • one year ago

Help me Please!!!

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  1. YumYum247
    • one year ago
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  2. YumYum247
    • one year ago
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    @sweetburger

  3. IrishBoy123
    • one year ago
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    where are you stuck?

  4. YumYum247
    • one year ago
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    I've attempted to do all three questions on my own, but can you please check my work??? For question A....this is what i wrote...|dw:1442537315350:dw|

  5. YumYum247
    • one year ago
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    The reaction force would be the same (1000N left) since the mass of both stones A and B is the same.... so whatever force stone A was travelling at received the same force back from stone B and that's why it immediately stopped.

  6. YumYum247
    • one year ago
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    b) Determine the action force on stone B and its acceleration... Ans) Since the mass of both stones is the same, the applied force on stone A transferred the same force to the stone B. And therefore and it accelerated stone B with the same velocity.

  7. YumYum247
    • one year ago
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    c) Determine the velocity of stone B as it loses contact with A. I'm not really sure about think one, please help me.....!!! :")

  8. YumYum247
    • one year ago
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    @Astrophysics please come rescue me from this PLEASE!!!

  9. Astrophysics
    • one year ago
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    What is app?

  10. Astrophysics
    • one year ago
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    You need to be more consistent with your notation

  11. Astrophysics
    • one year ago
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    Oh applied?

  12. YumYum247
    • one year ago
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    yuss Faap = applied.

  13. YumYum247
    • one year ago
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    i meant Fapp = applied.

  14. Astrophysics
    • one year ago
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    Ok cool, so make your own FBD and label it

  15. YumYum247
    • one year ago
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    ok i'll do that, i can't draw it here tho, it takes too long :(

  16. YumYum247
    • one year ago
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    but my answers make sense right..

  17. Astrophysics
    • one year ago
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    I don't really know what you were doing

  18. YumYum247
    • one year ago
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    Please kindly see the question sheet i uploaded... :")

  19. Astrophysics
    • one year ago
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    Don't worry about being right now, lets try to get a systematic approach to it

  20. Astrophysics
    • one year ago
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    You need to understand the system before you start doing the math

  21. YumYum247
    • one year ago
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    yaah!! :D ok

  22. Astrophysics
    • one year ago
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    |dw:1442538995633:dw|

  23. Astrophysics
    • one year ago
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    So your first question is asking to find the acceleration of stone A and reaction force acting on it, |dw:1442539047977:dw|

  24. YumYum247
    • one year ago
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    yes.!

  25. Astrophysics
    • one year ago
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    When we deal with Newton's laws we set vertical and horizontal forces separately

  26. YumYum247
    • one year ago
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    ok.

  27. Astrophysics
    • one year ago
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    So what are the forces on the horizontal?

  28. YumYum247
    • one year ago
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    applied Force....

  29. YumYum247
    • one year ago
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    oh sorry...actio and reaction forces!!

  30. Astrophysics
    • one year ago
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    Yes, exactly!

  31. YumYum247
    • one year ago
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    so there is a force being applied to stone A which is moving in the right...

  32. YumYum247
    • one year ago
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    and in contrary the force that applied that force also experiences a reaction force in the opposite direction.

  33. YumYum247
    • one year ago
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    i'm referring to stone A so far,

  34. YumYum247
    • one year ago
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    so whatever pushed the stone A also felt the same force back.

  35. YumYum247
    • one year ago
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    So as it touches the stone B on the horizontal axis, the reaction force from stone B will push back on stone A which will cause the stone A to immediately stop. while the Stone B carries the net force recevied from stone A.

  36. Astrophysics
    • one year ago
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    Sort of, think about Newton's third law of motion

  37. Astrophysics
    • one year ago
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    I think you're starting to understand it, just mess around and see what you get

  38. YumYum247
    • one year ago
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    yah but in the case, there is no friction and most importantly the mass of both stones is the same....so therefore the net force that stone A is travelling at transfers the same force to the next stone. IF the mass of both stones were different then some of the energy would be utlized on moving that object on the horizontal axis...

  39. Astrophysics
    • one year ago
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    When you deal with the mass note that when they are together you have \[m= (m_A+m_B)\]

  40. YumYum247
    • one year ago
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    oh ok...so the moment they touch each other, the mass is combined? O_o

  41. YumYum247
    • one year ago
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    what about acceleration at that moment????

  42. Astrophysics
    • one year ago
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    That's what you have to figure out :)

  43. YumYum247
    • one year ago
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    Yah that's why i'm here XD

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