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YumYum247
 one year ago
Help me Please!!!
YumYum247
 one year ago
Help me Please!!!

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IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0where are you stuck?

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1I've attempted to do all three questions on my own, but can you please check my work??? For question A....this is what i wrote...dw:1442537315350:dw

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1The reaction force would be the same (1000N left) since the mass of both stones A and B is the same.... so whatever force stone A was travelling at received the same force back from stone B and that's why it immediately stopped.

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1b) Determine the action force on stone B and its acceleration... Ans) Since the mass of both stones is the same, the applied force on stone A transferred the same force to the stone B. And therefore and it accelerated stone B with the same velocity.

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1c) Determine the velocity of stone B as it loses contact with A. I'm not really sure about think one, please help me.....!!! :")

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1@Astrophysics please come rescue me from this PLEASE!!!

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1You need to be more consistent with your notation

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1yuss Faap = applied.

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1i meant Fapp = applied.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Ok cool, so make your own FBD and label it

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1ok i'll do that, i can't draw it here tho, it takes too long :(

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1but my answers make sense right..

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1I don't really know what you were doing

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1Please kindly see the question sheet i uploaded... :")

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Don't worry about being right now, lets try to get a systematic approach to it

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1You need to understand the system before you start doing the math

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1dw:1442538995633:dw

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1So your first question is asking to find the acceleration of stone A and reaction force acting on it, dw:1442539047977:dw

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1When we deal with Newton's laws we set vertical and horizontal forces separately

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1So what are the forces on the horizontal?

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1oh sorry...actio and reaction forces!!

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1so there is a force being applied to stone A which is moving in the right...

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1and in contrary the force that applied that force also experiences a reaction force in the opposite direction.

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1i'm referring to stone A so far,

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1so whatever pushed the stone A also felt the same force back.

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1So as it touches the stone B on the horizontal axis, the reaction force from stone B will push back on stone A which will cause the stone A to immediately stop. while the Stone B carries the net force recevied from stone A.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Sort of, think about Newton's third law of motion

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1I think you're starting to understand it, just mess around and see what you get

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1yah but in the case, there is no friction and most importantly the mass of both stones is the same....so therefore the net force that stone A is travelling at transfers the same force to the next stone. IF the mass of both stones were different then some of the energy would be utlized on moving that object on the horizontal axis...

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1When you deal with the mass note that when they are together you have \[m= (m_A+m_B)\]

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1oh ok...so the moment they touch each other, the mass is combined? O_o

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1what about acceleration at that moment????

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1That's what you have to figure out :)

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1Yah that's why i'm here XD
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