Help with exponents. MEDAL!! Question posted below ...

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Help with exponents. MEDAL!! Question posted below ...

Mathematics
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\[7v^3 \times 10u^3v^5 \times 8uv^3\]
don't you multiply \(\bf{7*10*8}\) and add the exponents?

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Other answers:

Okay so if we do that then we will have \[7 \times 10 \times 8 = 560\] But how do i add the exponents?
\(v^3+v^5+v^3=3+5+3=11\\v^11\\u^3+u^1\\3+1=4\\u^4\)
\(v^3+v^5+v^3=v^{11}\)
add numbers keep same variable
So would my answer be 560v^11v^4 ?
You wrote two v's your u variable is missing.
Sorry i meant 560v^11u^4
Am I correct?
I really need help on this.
Correct, sorry.
Okay thank you. So I am going to do the next one: \[\large 9xy^2 \times 9x^5y^2\]
\[\large 9x^1y^2 \times 9x^5y^2 = 81x^6y^4\]
correct
Can i check more with you?
absolutely :)
\[6m^3n^3 \times 8m^2n^3 = 48m^5n^6\]
correct again :)
\[6x^2 \times 6x^3y^4 = 36x^5y^4\]
correct :)
\[7u^2v^5 \times 9uv^3 = 63u^3v^8\]
correct (:
\[uv \times 4uv^5 = 4u^2v^6\]
and correct once again c:
\[10xy^3 \times 8x^5y^3 = 80x^6y^6\]
correct
\[3u^4v^5 \times 7u^2v^3 = 21u^6v^8\]
correct :)
\[(2x^2)^2 = 2x^4\]
\[(p^4)^4 = p^16\]
\[(2x^2)^2 = 2x^4\]
uh-oh
just in case if you want to ask for (p^4)^4, my answer is p^16
Use the formula \(\bf\Huge (ab)^m = a^mb^m\)
That one is correct For that question, in latex you have to put p^{16}
\[p^{16}\]
But \(\bf\Large (2x^2)^2 \neq 2x^4\)
So use the formula I gave you :)
\[\large 2^2 \times (x^2)^2\]
\[4 \times x^4\] ?
correct :D
@AbdullahM I juts want to make sure a couple more if u have no problem :)
I would love to :)
thank you!
\[(k^3)^4\]
= \[k^12 \]
correct :)
sorry i forgot the latex
\[k^{12}\]
OH wait..
\[7^2 \times k^2 = 12 \times k^2\]
i meant 14
\[\large 14 \times k^2\]
So the question is \(\bf\Large 7^2 \times k^2 = 14 \times k^2\)
yes am i correct?
No... \(\bf\Large 7^2 = 7\times 7\neq 2\times 7\)
oh my god.. silly mistake ! sorry i meant to say 49 x k^2
good :)
\[\large (2b^2)^4 = 2^4 \times (b^2)^4 = 16b^8 \]
sorry but can u just say correct or incorrect really quickly? i need to go.
correct
sorry, I was looking at another tab :p
thank you so much for ur help! i truly appreciate it :)
sorry one quick question
sure :D
\[2n^4 \times 5n^4 = 10n^8\]
and \[2n^4 \times 6n^4 = 12n^8 \]
those are basically the same
correct for both :D

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