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anonymous

  • one year ago

A cyclist stops at a stop sign. After he checks the intersection, he begins pedaling again. He reaches a velocity of six meters per second in three seconds. What's the cyclist's acceleration? HELP ME PLEASE

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  1. shreenithaa
    • one year ago
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    first write the formula

  2. shreenithaa
    • one year ago
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    what is it? i need to write it so i can talk u through this,okay?

  3. anonymous
    • one year ago
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    What do you mean the formula? Oh gosh I am not good at this!

  4. anonymous
    • one year ago
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    That is all that is there

  5. kl0723
    • one year ago
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    can you use velocity = intial velocity + accel x time? do you think you have all the data required?

  6. anonymous
    • one year ago
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    I have the initial velocity. That is 0. The velocity now is 2 m/s2 (That is squared. I do not know what direction the person is going) Time is 3 seconds I need the acceleration

  7. anonymous
    • one year ago
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    v=u+at

  8. kl0723
    • one year ago
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    since the cyclist stops and the starts to pedal again means that he starts from rest, then initial velocity is zero, you're given time and final velocity or max velocity in this case

  9. anonymous
    • one year ago
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    u=0 v=2m/s t=3 s a=?

  10. anonymous
    • one year ago
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    Yes?

  11. kl0723
    • one year ago
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    from the equation can you solve for Acceleration and then plug in your data?

  12. shreenithaa
    • one year ago
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    well, first of all, the formula is velocity equals distance divided by time acceleration is velocity final minus velocity intial over time final minus time intitial

  13. shreenithaa
    • one year ago
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    use this info to calculate ur math

  14. anonymous
    • one year ago
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    so it is 6 - 0 / and 3 - 0? so the acceleration is 2?

  15. shreenithaa
    • one year ago
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    velocity is 2 but u need final velocity and the starting velocity and final time and beginning time in order to get the acceleration we know that final time is 3 seconds

  16. anonymous
    • one year ago
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    I have the final velocity though. It is 2 m/s (Squared) the direction is not given. What I gave is what I have

  17. shreenithaa
    • one year ago
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    what if the starting time is 0 so now we need the initial velocity

  18. anonymous
    • one year ago
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    initial velocity is 0 m/s (Squared) since they are at a stop sign

  19. shreenithaa
    • one year ago
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    since the starting is 0 so the velocity must be 0 right?

  20. anonymous
    • one year ago
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    Yes

  21. shreenithaa
    • one year ago
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    so ur answer is acceleration is 2

  22. anonymous
    • one year ago
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    That is it?

  23. shreenithaa
    • one year ago
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    u were right the whole time sorry for the confusion

  24. anonymous
    • one year ago
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    The answer is just 2?

  25. shreenithaa
    • one year ago
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    no it has to have the units

  26. anonymous
    • one year ago
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    What are said units? Like are the from the problem, or?

  27. anonymous
    • one year ago
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    I just started physics recently, and boy is it hard!

  28. shreenithaa
    • one year ago
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    meters per second squared

  29. shreenithaa
    • one year ago
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    what grade r u in and state

  30. anonymous
    • one year ago
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    8th, texas

  31. anonymous
    • one year ago
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    Thank you, SO MUCH!

  32. shreenithaa
    • one year ago
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    8th California

  33. anonymous
    • one year ago
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    Cool! I'm just not very smart!

  34. anonymous
    • one year ago
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    2=0+a*3 a=2/3 m/s^2

  35. anonymous
    • one year ago
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    I er, have no idea what that means if we are being honest here

  36. shreenithaa
    • one year ago
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    wow same grad right!!! i moved to virginia where i had honors science so i learned this i was in cali for most of the time dont worry i am dumb in many places,but math and science are my specialty u'll find urs

  37. anonymous
    • one year ago
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    But thanks. Really!|dw:1442535044863:dw|

  38. anonymous
    • one year ago
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    \[v=u+at\] \[2=0+a*3\] 3a=2 \[a=\frac{ 2 }{ 3 }m/s^2\]

  39. shreenithaa
    • one year ago
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    ur welcome good luck;)

  40. anonymous
    • one year ago
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    Thanks!

  41. shreenithaa
    • one year ago
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    wait what r u talking about @surjithayer

  42. anonymous
    • one year ago
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    I don't know either! lol

  43. shreenithaa
    • one year ago
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    k gotto go

  44. anonymous
    • one year ago
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    Bye!

  45. shreenithaa
    • one year ago
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    do u have a texasian accent?

  46. anonymous
    • one year ago
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    The closest thing to an accent is that I say y'all. Other than that, no

  47. shreenithaa
    • one year ago
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    i like accents mostly british, canadian, and australian

  48. anonymous
    • one year ago
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    Gee, thanks! Lol

  49. shreenithaa
    • one year ago
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    thnx for what?

  50. anonymous
    • one year ago
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    (sarcasm)

  51. shreenithaa
    • one year ago
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    ooooh... i knew that

  52. anonymous
    • one year ago
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    (It is like thanks for being mean, but a joke)

  53. anonymous
    • one year ago
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    lol

  54. anonymous
    • one year ago
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    sorry ,i miss read ,it is 6 m/s i thought 2 m/s you are correct 6=0+3a a=2 m/s^2

  55. shreenithaa
    • one year ago
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    hey! i like them i never said i didnt like urs

  56. shreenithaa
    • one year ago
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    well @surjithayer we already got that thnx for helping anyways

  57. anonymous
    • one year ago
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    (that is why I was kidding) and thanks @surjithayer

  58. shreenithaa
    • one year ago
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    i have a friend who i met or met online she's like my study-budy penpel i guess ur mine now too she's in florida but in 6th grade

  59. shreenithaa
    • one year ago
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    sorry penpal

  60. shreenithaa
    • one year ago
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    i have spelling issues

  61. anonymous
    • one year ago
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    lol. That is cool I guess. I am doing the rest of my hw rn too, it is way easier

  62. shreenithaa
    • one year ago
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    k bye im doing mine and helping

  63. anonymous
    • one year ago
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    bye!

  64. shreenithaa
    • one year ago
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    hope i meet u tom-tom (tomorrow in my way) it not tom and jerry

  65. anonymous
    • one year ago
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    YES, I am done with my homework! YAY

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