A community for students.
Here's the question you clicked on:
 0 viewing
hpfan101
 one year ago
What is the limit as x approaches 2 of the function (1/x  1/3)/(x3)?
The fractions part of the problem made me confused and get the wrong answer.
hpfan101
 one year ago
What is the limit as x approaches 2 of the function (1/x  1/3)/(x3)? The fractions part of the problem made me confused and get the wrong answer.

This Question is Closed

hpfan101
 one year ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow 3} (\frac{ 1 }{ x }  \frac{ 1 }{ 3 })/(x3) \]

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1what would you get for.. say \(\bf \cfrac{1}{x}\cfrac{1}{3}?\)

hpfan101
 one year ago
Best ResponseYou've already chosen the best response.0You'd get 0 when you subsitute 3 for x.

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1well.. I meant the numerator only :)

hpfan101
 one year ago
Best ResponseYou've already chosen the best response.0The only thing I don't get is that I got 0 both in the numerator and the denominator. Not sure what to do next.

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1right... one sec bear in mind that \(\bf ab \iff (ba)\) one sec

jdoe0001
 one year ago
Best ResponseYou've already chosen the best response.1\(\bf \lim\limits_{x\to 3}\ \cfrac{\frac{1}{x}\frac{1}{3}}{x3} \\ \quad \\ \cfrac{\frac{3x}{3x}}{x3}\implies \cfrac{\frac{3x}{3x}}{\frac{x3}{1}}\implies \cfrac{3x}{3x}\cdot \cfrac{1}{x3} \\ \quad \\ \cfrac{3x}{3x(x3)}\implies \cfrac{{\color{brown}{ \cancel{(x3)}}}}{3x\cancel{(x3)}}\)

hpfan101
 one year ago
Best ResponseYou've already chosen the best response.0Oh, now I see what I was supposed to do! Thank you very much!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.