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Yes or no are the answer choices

So, you have to solve for the zeros of the function. What are they?

I'm honestly not sure how to find them

use demos graph to see where they cut x-axis

(2.2,0)

So would the answer be no since it's (2.2,0) and 4 would be a higher bound and not lower bound?

we don't have 0. please check

what do you mean? it cut the x-axis at 2.2

but you can use it. now find f(0) =?

replace 0 into f(x) , what do you get?

|dw:1442536923437:dw|

-5

ok, so f(0) =-5 < 0 , right?
now f (2) =?

-3

So what does that mean

that mean from 0 to 2 you still not pass the x-axis, since f(x) <0 for both. Now test f(3)

22

Now, use synthetic,

forget it, short cut

okay haha

|dw:1442537533408:dw|

now, fill up

Again, the lesson didnt really explain this stuff so I'm not sure how to use that

you don't know synthetic?

not completely, looking it up now trying to learn real quick

|dw:1442537680182:dw|

|dw:1442537714109:dw|

now 4 *6 =?

24

|dw:1442537779766:dw| got it?

the last one, you do, the same

would it be 4*21 = 84 or 4*24 =96?

|dw:1442537857152:dw|

oh okay i see

that's easy then haha

|dw:1442538058710:dw|

ok, now,
4 >0 , right?

yes

look at the bottom row, they are 2,6,21,79 right?

yes

and all them are positive, right?

yes

Hence 4 is upper bound for the zeros

woah i see, a lot goes into it

so back to the original question the answer would be no

yup

ok thanks for all of the help, what would happen if one of them was negative?

you test, if k <0, the bottom line is +, -,+,- alternatively, then k is lower bound

learn from it http://www.howe-two.com/mathematicat/bound.html