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hpfan101

  • one year ago

How to find the limit of a funciton with radicals?

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  1. hpfan101
    • one year ago
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    \[\lim_{x \rightarrow 0} \left( \frac{ \sqrt{1+x}-\sqrt{1-x} }{ x } \right)\]

  2. hpfan101
    • one year ago
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    \[ \left( \frac{ \sqrt{1+x}-\sqrt{1-x} }{ x } \right) \times \left( \frac{ \sqrt{1+x} +\sqrt{1-x}}{ \sqrt{1+x}+\sqrt{1-x} } \right)\]

  3. hpfan101
    • one year ago
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    After multiplying by the conjugate, this is what I got: \[ \left( \frac{ {(1+x)}-{(1-x)} }{ (x)(\sqrt{1+x}+\sqrt{1-x}) } \right)\]

  4. hpfan101
    • one year ago
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    Not sure what to do about the denominator but the numerator would simplify to just 2x.

  5. anonymous
    • one year ago
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    leave the denominator in factored for cancel the x top and bottom, then plug in 0

  6. anonymous
    • one year ago
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    nice \(\LaTeX\) btw !!

  7. hpfan101
    • one year ago
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    @satallite73: Thanks!

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