FAN AND MEDAL!!
Find the value of x so that the rectangles have the same area.

- anonymous

FAN AND MEDAL!!
Find the value of x so that the rectangles have the same area.

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- anonymous

|dw:1442538186565:dw|

- anonymous

@Hero , @Here_to_Help15 , @nincompoop , @satellite73 , @Tazmaniadevil

- anonymous

@Astrophysics

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## More answers

- anonymous

@dm91

- anonymous

anybody there

- sidmanfu

Ill ask someone that I know to help you ;)

- anonymous

ok

- anonymous

@mathmate , @Hero , @HaileyD

- anonymous

@emily_wilson

- sidmanfu

;)

- anonymous

i tried but its so confusing i dunno where to start

- mathmate

Hint: start with
Area = length * width.
|dw:1442539241188:dw|

- anonymous

i still dont understand

- mathmate

If the rectangles have the same area, then
L1*W1=L2*W2
Substitute the numbers from the figure and solve for x.

- anonymous

ok and how do i solve for x

- anonymous

@dan815

- anonymous

anybody there

- anonymous

@mathmate where did u go

- sidmanfu

hes still there lol XD

- anonymous

it seems like hes frozen

- anonymous

anybody help

- dm91

ok sorry went offline for a bit what do you need help with?

- mathmate

I suggest you formulate the equation before trying to solve it.
So could you substitute values L1, W1, L2, W2 and form an equation?

- anonymous

how do u do that

- dm91

or L*W*H

- mathmate

There is no height, so L1*W1=L2*W2, we're calculating areas.

- anonymous

ok?

- mathmate

So can you formulate the equation? The values to be substituted is in the diagram.

- mathmate

*are

- anonymous

i know but what do i substitute with

- Jhannybean

\[L_1=~? \\ L_2=~? \\ W_1=~? \\ W_2=~? \\\]

- Jhannybean

Find those, then use this formula he gave you.
\(\color{#0cbb34}{\text{Originally Posted by}}\) @mathmate
There is no height, so \(\color{red}{L1*W1=L2*W2}\) , we're calculating areas.
\(\color{#0cbb34}{\text{End of Quote}}\)

- anonymous

ok

- anonymous

@@phi

- anonymous

@phi

- anonymous

im really confused this is is not going to get me anywhere. how do we do that?

- dm91

i ahve one person that can explain it better
@steve816

- phi

How far did you get ?

- dan815

|dw:1442540874878:dw|

- anonymous

i didnt know where to start i was completely confused

- dan815

start with that

- phi

Do you understand area is length times width ?

- anonymous

yes

- phi

do you know the width and length of your first rectangle (on the left side) ?

- anonymous

yes w=9, l=x-4

- phi

ok. now multiply them to get area
to multiply put parens around (x-4)
and just write it as
9(x-4)
that is algebra short-hand for 9 times (x-4)
ok so far?

- anonymous

YES! I THINK I GET IT! Just wait so that I can solve it.

- phi

can you do the same thing for the other triangle ?

- anonymous

u mean rectangle

- phi

oops, yes rectangle

- anonymous

ok ill try just wait but pls dont leave

- anonymous

is x=25??

- anonymous

@phi am i right

- anonymous

im sorry for being late i was confused again at first

- anonymous

@phi are u even there

- anonymous

ok i believe thats right because both rectangles have the same area with that value

- phi

yes x=25
how did you get it ?

- anonymous

i first used the distributive property to simplify, then used inverse subtraction, then inverse addition, then inverse division and then TADAA! I got my answer! YAY!

- anonymous

thanks for all the help @phi and @mathmate

- phi

yw

- anonymous

u guys r the best

- anonymous

bye

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