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teller

  • one year ago

Can someone make sure I did this right? Suppose that the functions r and s are defined for all real numbers x as follows. r(x)=x+6 s(x)=2x-4 Write the expressions for (s+r)(x) and (s-r)(x) and evaluate (s.r)(1) (s+r)(x)=(2x-4)+(x+6) s-r)(x)=(2x-4)-(x+6) (s.r)(1)= 2(x-2) over x+6

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  1. anonymous
    • one year ago
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    right but you are not done

  2. anonymous
    • one year ago
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    for the first two, combine like terms

  3. teller
    • one year ago
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    So it would be (s+r)(x)= (2x-x)+(4+6) (s-r)(x)=2x-x)-(4+6)

  4. teller
    • one year ago
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    For the last part I know I got wrong because my thing doesn't have a fraction sign so I know that that can't be my answer.

  5. anonymous
    • one year ago
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    \[(s+r)(x)=(2x-4)+(x+6)=3x+2\]

  6. teller
    • one year ago
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    what's that for ?

  7. teller
    • one year ago
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    where did you get the 2x+2?

  8. anonymous
    • one year ago
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    that is what you get when you combine like terms

  9. teller
    • one year ago
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    but the problem has a divide symbol .. not a plus

  10. teller
    • one year ago
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    wouldn't you divide?

  11. anonymous
    • one year ago
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    i copied and pasted what you wrote

  12. anonymous
    • one year ago
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    for number 1

  13. teller
    • one year ago
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    I'm confused... so that would be for the first one?

  14. anonymous
    • one year ago
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    yes

  15. teller
    • one year ago
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    So the second one would be (s+r)(x)=(2x−4)-(x+6)=x-10?

  16. teller
    • one year ago
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    so what would the last choice be ?

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spraguer (Moderator)
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