teller
  • teller
Can someone make sure I did this right? Suppose that the functions r and s are defined for all real numbers x as follows. r(x)=x+6 s(x)=2x-4 Write the expressions for (s+r)(x) and (s-r)(x) and evaluate (s.r)(1) (s+r)(x)=(2x-4)+(x+6) s-r)(x)=(2x-4)-(x+6) (s.r)(1)= 2(x-2) over x+6
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
right but you are not done
anonymous
  • anonymous
for the first two, combine like terms
teller
  • teller
So it would be (s+r)(x)= (2x-x)+(4+6) (s-r)(x)=2x-x)-(4+6)

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teller
  • teller
For the last part I know I got wrong because my thing doesn't have a fraction sign so I know that that can't be my answer.
anonymous
  • anonymous
\[(s+r)(x)=(2x-4)+(x+6)=3x+2\]
teller
  • teller
what's that for ?
teller
  • teller
where did you get the 2x+2?
anonymous
  • anonymous
that is what you get when you combine like terms
teller
  • teller
but the problem has a divide symbol .. not a plus
teller
  • teller
wouldn't you divide?
anonymous
  • anonymous
i copied and pasted what you wrote
anonymous
  • anonymous
for number 1
teller
  • teller
I'm confused... so that would be for the first one?
anonymous
  • anonymous
yes
teller
  • teller
So the second one would be (s+r)(x)=(2x−4)-(x+6)=x-10?
teller
  • teller
so what would the last choice be ?

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