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- teller

Can someone make sure I did this right?
Suppose that the functions r and s are defined for all real numbers x as follows.
r(x)=x+6
s(x)=2x-4
Write the expressions for (s+r)(x) and (s-r)(x) and evaluate (s.r)(1)
(s+r)(x)=(2x-4)+(x+6)
s-r)(x)=(2x-4)-(x+6)
(s.r)(1)= 2(x-2) over x+6

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- teller

- schrodinger

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- anonymous

right but you are not done

- anonymous

for the first two, combine like terms

- teller

So it would be
(s+r)(x)= (2x-x)+(4+6)
(s-r)(x)=2x-x)-(4+6)

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- teller

For the last part I know I got wrong because my thing doesn't have a fraction sign so I know that that can't be my answer.

- anonymous

\[(s+r)(x)=(2x-4)+(x+6)=3x+2\]

- teller

what's that for ?

- teller

where did you get the 2x+2?

- anonymous

that is what you get when you combine like terms

- teller

but the problem has a divide symbol .. not a plus

- teller

wouldn't you divide?

- anonymous

i copied and pasted what you wrote

- anonymous

for number 1

- teller

I'm confused... so that would be for the first one?

- anonymous

yes

- teller

So the second one would be (s+r)(x)=(2x−4)-(x+6)=x-10?

- teller

so what would the last choice be ?

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