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anonymous
 one year ago
If f(−3)=−4 and f′(−3)=6, find the equation of the tangent line to f at x=−3.
a) y=−4x+6
b) y=6x+14
c) y=−4x−6
d) y=6x−4
e) y=6x−22
anonymous
 one year ago
If f(−3)=−4 and f′(−3)=6, find the equation of the tangent line to f at x=−3. a) y=−4x+6 b) y=6x+14 c) y=−4x−6 d) y=6x−4 e) y=6x−22

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know that the slope is f'(x) so 6, I'm just not sure what to do the rest of the way.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@satellite73 this is my last question of the night, could you help?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0use the points slope form

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i know m but how to i get y1 and x1?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[m=6,(x_1,x_2)=(3,4)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you don't get them, you are told them

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh! that makes sense! thank you.
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