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clara1223

  • one year ago

If f(−3)=−4 and f′(−3)=6, find the equation of the tangent line to f at x=−3. a) y=−4x+6 b) y=6x+14 c) y=−4x−6 d) y=6x−4 e) y=6x−22

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  1. clara1223
    • one year ago
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    I know that the slope is f'(x) so 6, I'm just not sure what to do the rest of the way.

  2. clara1223
    • one year ago
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    @satellite73 this is my last question of the night, could you help?

  3. anonymous
    • one year ago
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    use the points slope form

  4. clara1223
    • one year ago
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    y-y1=m(x-x1)

  5. clara1223
    • one year ago
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    i know m but how to i get y1 and x1?

  6. anonymous
    • one year ago
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    \[m=6,(x_1,x_2)=(-3,-4)\]

  7. anonymous
    • one year ago
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    you don't get them, you are told them

  8. clara1223
    • one year ago
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    Oh! that makes sense! thank you.

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