Anguyennn
  • Anguyennn
(x-1)^2-13=3, how do you find the x?
Mathematics
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
add 13 take the square root, don't forget the \(\pm\) then add 1
Anguyennn
  • Anguyennn
what?
anonymous
  • anonymous
add 13 to both sides what do you get?

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More answers

Anguyennn
  • Anguyennn
16
anonymous
  • anonymous
actually you get \[(x-1)^2=16\]
Anguyennn
  • Anguyennn
yes
anonymous
  • anonymous
can you think of a number whose square is 16?
Anguyennn
  • Anguyennn
4
anonymous
  • anonymous
ok so we can solve \(x-1=4\) easily enough now can you think of another number whose square is 16 (hint, it is negative)
Anguyennn
  • Anguyennn
Anguyennn
  • Anguyennn
-4?
anonymous
  • anonymous
yes
anonymous
  • anonymous
so you have two equations to solve \[x-1=4\] and also \[x-1=-4\]
Anguyennn
  • Anguyennn
so will x be x=-5 and x=3
anonymous
  • anonymous
no
anonymous
  • anonymous
to solve \[x-1=4\]you need to ADD 1 to both sides
Anguyennn
  • Anguyennn
5
Anguyennn
  • Anguyennn
and -3

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