Anguyennn one year ago (x-1)^2-13=3, how do you find the x?

1. anonymous

add 13 take the square root, don't forget the $$\pm$$ then add 1

2. Anguyennn

what?

3. anonymous

add 13 to both sides what do you get?

4. Anguyennn

16

5. anonymous

actually you get $(x-1)^2=16$

6. Anguyennn

yes

7. anonymous

can you think of a number whose square is 16?

8. Anguyennn

4

9. anonymous

ok so we can solve $$x-1=4$$ easily enough now can you think of another number whose square is 16 (hint, it is negative)

10. Anguyennn

11. Anguyennn

-4?

12. anonymous

yes

13. anonymous

so you have two equations to solve $x-1=4$ and also $x-1=-4$

14. Anguyennn

so will x be x=-5 and x=3

15. anonymous

no

16. anonymous

to solve $x-1=4$you need to ADD 1 to both sides

17. Anguyennn

5

18. Anguyennn

and -3