(x-1)^2-13=3, how do you find the x?

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(x-1)^2-13=3, how do you find the x?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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add 13 take the square root, don't forget the \(\pm\) then add 1
what?
add 13 to both sides what do you get?

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Other answers:

16
actually you get \[(x-1)^2=16\]
yes
can you think of a number whose square is 16?
4
ok so we can solve \(x-1=4\) easily enough now can you think of another number whose square is 16 (hint, it is negative)
-4?
yes
so you have two equations to solve \[x-1=4\] and also \[x-1=-4\]
so will x be x=-5 and x=3
no
to solve \[x-1=4\]you need to ADD 1 to both sides
5
and -3

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