Pulsified333
  • Pulsified333
about events A and B of a sample space S, but assume that Pr[A′]=0.3, Pr[B]=0.5, and Pr[A′∩B]=0.2. Find the probabilities of the following events: (1) Pr[A∩B]= (2) Pr[A∪B]= (1) Pr[A′∪B]=
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Pulsified333
  • Pulsified333
@dan815
anonymous
  • anonymous
|dw:1442540376873:dw|
anonymous
  • anonymous
do you know where \(A'\cap B\) is in the picture ?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

Pulsified333
  • Pulsified333
B
anonymous
  • anonymous
shade it in not B, but \(A'\cap B\)
Pulsified333
  • Pulsified333
then what is A′∩B
anonymous
  • anonymous
the stuff in B that is not in A
Pulsified333
  • Pulsified333
|dw:1442540600013:dw|
anonymous
  • anonymous
got it now lets put a \(0.2\) there |dw:1442540629245:dw|
Pulsified333
  • Pulsified333
so that mean A U B is .3
anonymous
  • anonymous
what you really mean is \[P(A\cap B)=0.3\] and the answer is yes
Pulsified333
  • Pulsified333
yes my bad
anonymous
  • anonymous
|dw:1442540747197:dw|
Pulsified333
  • Pulsified333
then how does A' is .3
anonymous
  • anonymous
the .2 is in \(A'\) cause it is not in A also the stuff outside of both in in A' you used up .2 in B, that leaves only .1 outside
anonymous
  • anonymous
|dw:1442540852342:dw|
Pulsified333
  • Pulsified333
so A = .4
anonymous
  • anonymous
now all that is left to do is figure out what goes in \(A\cap B'\) the missing part all this has to add up to 1, so make sure it does
anonymous
  • anonymous
yeah right
anonymous
  • anonymous
|dw:1442540918987:dw|
anonymous
  • anonymous
now you can figure out any probability you like from the picture, so long as you know what the set is

Looking for something else?

Not the answer you are looking for? Search for more explanations.