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\[v _{f}=v _{i}+at\]
where vf is final velocity
vi is initial velocity
a is acceleration
t is time.

They are all in cm, so you dont have to convert.

So Vf = .67 + (-.0059)(.58)?

Ask yourself: What is this problem looking for?

and what is given?

It's wanting the amount of seconds to reach .58 cm/s.
The inital and acceleration are given.

How many seconds would it take to reach a velocity of +0.58 cm/s?
Final velocity is given too.

You are right.
They want seconds which is time (t)
Now plug in the formula again.

-0.0059=(.58-.67)/(t)

Would that be the set up?

Yes, that is correct.
It would be better if you the t by itself though.

And you divide the -0.0059 by (.58-.67)?

Yea thats like algebra right there.

So I should get 15.25423729

Looks correct!

And what your answer be in sf?

15

Yes!

Thanks for the help

No problem!
The answer is 15 seconds btw or just 15 s