steve816
  • steve816
Circle question. How would I convert this to standard form?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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steve816
  • steve816
\[x^2+y^2+4x-4y-1=0\]
steve816
  • steve816
@jim_thompson5910 Do you think you can help me with this?
jim_thompson5910
  • jim_thompson5910
focus on just x^2 + 4x what's missing to complete the square?

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steve816
  • steve816
Oh, so we have to complete the square for both x and y?
jim_thompson5910
  • jim_thompson5910
correct
steve816
  • steve816
for x it would be 4 and for y, it would also be 4 I think.
jim_thompson5910
  • jim_thompson5910
yeah x^2 + 4x + 4 is a perfect square
jim_thompson5910
  • jim_thompson5910
so you have to add 4 to both sides to go from x^2 + 4x to x^2 + 4x + 4
steve816
  • steve816
Yes, and that can be simplified to (x+2)^2
steve816
  • steve816
I think I'm understanding this!
jim_thompson5910
  • jim_thompson5910
yep x^2 + 4x + 4 factors to (x+2)^2
steve816
  • steve816
I did the math and I got (x+2)^2+(y-2)^2=1
jim_thompson5910
  • jim_thompson5910
you forgot to add 4 to both sides. You only added to the left side
jim_thompson5910
  • jim_thompson5910
you're adding 2 copies of 4 actually
steve816
  • steve816
oh OOPS I forgot!
steve816
  • steve816
so it would be (x+2)^2+(y-2)^2=9
jim_thompson5910
  • jim_thompson5910
bingo
steve816
  • steve816
Thank you :D
jim_thompson5910
  • jim_thompson5910
no problem

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