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nosnip
 one year ago
How to I factorise/solve this equation?
nosnip
 one year ago
How to I factorise/solve this equation?

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nosnip
 one year ago
Best ResponseYou've already chosen the best response.1\[y ^{2}  x  6x ^{2}\]

nosnip
 one year ago
Best ResponseYou've already chosen the best response.1Do you know what type of equation it even is so I can google it?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2you can rearrange it \[y^2−x−6x^2 = 0\] \[0 = 6x^2+xy^2\] so it looks like a quadratic, where \(a= 6\), \(b=1\), \(c=y^2\) solve with the quadratic formula

nosnip
 one year ago
Best ResponseYou've already chosen the best response.1ah okay that's I wasn't sure if it was a quadratic :)

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2(i'm assuming there is no other information give about y)

nosnip
 one year ago
Best ResponseYou've already chosen the best response.1well it's part of a simultaneous equation? I'm confused because it's a noncalculator question and this seems difficult without a calculator

nosnip
 one year ago
Best ResponseYou've already chosen the best response.1\[y  3x + 2 = 0\] \[y ^{2}  x  6x ^{2} = 0\]

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2so you have two equations?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2What do you get if you solve the first one \[y3x+2=0\]for \(y\)?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2substitute this into the second equation \[y^2−x−6x^2=0\\ \downarrow\\ (3x + 2)^2x6x^2 =0\] This is a quadratic equation in \(x\), solve for both values of \(x\)

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2(after simplifying)

nosnip
 one year ago
Best ResponseYou've already chosen the best response.1okay give me a second :)

nosnip
 one year ago
Best ResponseYou've already chosen the best response.1Do you get the quadratic \[3x ^{2} + 11x + 4 = 0\]

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2almost, but the middle term isn't right

nosnip
 one year ago
Best ResponseYou've already chosen the best response.1I'm not sure what else it could be?

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2What did you get for the expansion of \[(3x2)^2=\]

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2\[(ab)^2=a^22ab+b^2\]

nosnip
 one year ago
Best ResponseYou've already chosen the best response.1I'm still not seeing where I went wrong sorry!

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2the +12 should be 12

nosnip
 one year ago
Best ResponseYou've already chosen the best response.1ooh yes sorry you're right okay I can do it myself from there thankyou :)

nosnip
 one year ago
Best ResponseYou've already chosen the best response.1I've got to go out but thatnlyou for your help I will give it a go later

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.2you should now use the quadratic formula on the right (simplified) quadratic equation to get two nice values of x, then back substitute into equation 1, to get the corresponding y's
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