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anonymous

  • one year ago

Find the x- and y-intercepts of the graph of the equation? x^2+y^2=64 I changed it to slope-intercept which is y=x+64 right? 64 is the y-intercept right? what is the x intercept? and did I change the equation correctly?

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  1. anonymous
    • one year ago
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    Ahhh, sorry, I am a bit confused so there are no x-intercepts? And what about y? :)

  2. UnkleRhaukus
    • one year ago
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    the two y intercepts are for when x=0 and the two x intercepts are when y=0

  3. anonymous
    • one year ago
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    So do I have to find a way to make x=0 and y=0? :)

  4. UnkleRhaukus
    • one year ago
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    when x =0 0^2+y^2 = 64 what can y be?

  5. anonymous
    • one year ago
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    Oh, 8? :)

  6. UnkleRhaukus
    • one year ago
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    yes 8 and ?

  7. anonymous
    • one year ago
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    -8? orrr? :)

  8. UnkleRhaukus
    • one year ago
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    good so the two y-intercepts are at (0,8), and (0,-8)

  9. UnkleRhaukus
    • one year ago
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    can you get the x-intercepts too?

  10. anonymous
    • one year ago
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    Okay, thank you very much! So, wouldn't x be the same? Or no? :)

  11. UnkleRhaukus
    • one year ago
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    the values will be the same, but the coordinate pairs will be the other way around

  12. anonymous
    • one year ago
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    Okay, I understand now! Thank you very much for your help! :)

  13. UnkleRhaukus
    • one year ago
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    no you have all four intercepts, can you predict the 2D shape that the relation represents ?

  14. anonymous
    • one year ago
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    hmmm........ is it a flat horizontal line?

  15. anonymous
    • one year ago
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    actually wait...

  16. UnkleRhaukus
    • one year ago
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    |dw:1442556310188:dw|

  17. anonymous
    • one year ago
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    it's almost like a diamond??

  18. UnkleRhaukus
    • one year ago
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    it's a circle of radius 8! |dw:1442556339192:dw|

  19. anonymous
    • one year ago
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    Ohhhhhhhhhhhhhhhhhh, hahaha, I'm sorry, I'm bad at math. That makes sense, thank you for helping me so much! :)

  20. UnkleRhaukus
    • one year ago
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    you will remember the equation of a circle now (centred at the origin, with radius r) \[x^2 + y^2 = r^2\]

  21. anonymous
    • one year ago
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    Ohhh, I didn't even notice that, thank you, that will help me on my exam tomorrow :)

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