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- anonymous

Find the x- and y-intercepts of the graph of the equation?
x^2+y^2=64
I changed it to slope-intercept which is y=x+64 right? 64 is the y-intercept right? what is the x intercept? and did I change the equation correctly?

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- anonymous

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- anonymous

Ahhh, sorry, I am a bit confused so there are no x-intercepts? And what about y? :)

- UnkleRhaukus

the two y intercepts are for when x=0
and the two x intercepts are when y=0

- anonymous

So do I have to find a way to make x=0 and y=0? :)

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- UnkleRhaukus

when x =0
0^2+y^2 = 64
what can y be?

- anonymous

Oh, 8? :)

- UnkleRhaukus

yes 8 and ?

- anonymous

-8? orrr? :)

- UnkleRhaukus

good so the two y-intercepts are at (0,8), and (0,-8)

- UnkleRhaukus

can you get the x-intercepts too?

- anonymous

Okay, thank you very much! So, wouldn't x be the same? Or no? :)

- UnkleRhaukus

the values will be the same, but the coordinate pairs will be the other way around

- anonymous

Okay, I understand now! Thank you very much for your help! :)

- UnkleRhaukus

no you have all four intercepts, can you predict the 2D shape that the relation represents ?

- anonymous

hmmm........ is it a flat horizontal line?

- anonymous

actually wait...

- UnkleRhaukus

|dw:1442556310188:dw|

- anonymous

it's almost like a diamond??

- UnkleRhaukus

it's a circle of radius 8!
|dw:1442556339192:dw|

- anonymous

Ohhhhhhhhhhhhhhhhhh, hahaha, I'm sorry, I'm bad at math. That makes sense, thank you for helping me so much! :)

- UnkleRhaukus

you will remember the equation of a circle now
(centred at the origin, with radius r)
\[x^2 + y^2 = r^2\]

- anonymous

Ohhh, I didn't even notice that, thank you, that will help me on my exam tomorrow :)

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