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anonymous
 one year ago
Question involves spans & vectors, see attached picture.
anonymous
 one year ago
Question involves spans & vectors, see attached picture.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know I'm supposed to form a matrix, but I keep getting the answers wrong. Maybe I need to see one of these attempted by you.

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0What is the question exactly?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Let me get attach the question, I'm sorry I just noticed it was cut out from the pic I posted

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Just attached the question

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0And what was the modified version of the algorithm mentioned?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have no idea haha, all I know is to create a matrix using what's given

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lol I'm having trouble making a matrix on here

anonymous
 one year ago
Best ResponseYou've already chosen the best response.03 1 1 ; 3 5 1 2 ; 4 2 4 3 ; 5

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0how are you gonna get rid of the 5 , and 2, in the first column ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0working on it right now

anonymous
 one year ago
Best ResponseYou've already chosen the best response.01 5 2 ; 8 0 7 3 ; 11 0 14 7 ; 21

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0am I even doing the right thing lol

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2v1 v2 v3 S = {(3,5,2),(1,1,4),(1,2,3)} b = (3,4,5) can b be formed by a linear combination of the vectors in S? b = c1v1 + c2v2 + c3v3 ?? can we find coefficients that create b, from the vectors in S? c1v1 = 3(c1), 5(c1), 2(c1) c2v2 = 1(c2), 1(c2), 4(c2) c3v3 = 1(c3), 2(c3), 3(c3)  b = 3 , 4 , 5 in other words: 3(c1) + 1(c2) + 1(c3) = 3 5(c1) + 1(c2) + 2(c3) = 4 2(c1) + 4(c2)  3(c3) = 5 this conforms to the matrix that you wrote up to start your solution, so yes you are on the right track

amistre64
 one year ago
Best ResponseYou've already chosen the best response.23 1 1 3 5 1 2 4 2 4 3 5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So do I go for reduced row echelon form?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2the long version is to use elimination to solve the system of equation 3x + y + z = 3 5x + y + 2z = 4 2x +4y  3z = 5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0apparently the answer is 1/2 v1 + 3/2 v2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't get how that's the answer

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2it is quite possible that the vectors in S are not independant ... that one or more can be written as a linear combination of the others, what is the determinant of S? 3 1 1 5 1 2 2 4 3 1 1/3 1/3 1 1/5 2/5 1 2 3/2 1 1/3 1/3 0 2/15 1/15 0 7/3 7/6 1 1/3 1/3 0 1 1/2 0 1 1/2 1 1/3 1/3 0 1 1/2 0 0 0 1 0 1/2 0 1 1/2 0 0 0 ................... what this tells us is that v3 is redundant as far as an efficient span goes, v3 can be formed as a linear combination of v1 and v2, thereby making any combination with v3 simplifies to v1 and v2 alone. v3 = (v1v2)/2 3/2 1/2 = 1 5/2 1/2 = 2 2/2 4/2 = 3

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2is b, a linear combination of v1 and v2? seeing that v3 is redundant (v3 is in the same plane as v1 and v2) v1 v2 b 3 1 3 5 1 4 2 4 5 rref{{3,1,3},{5,1,4},{2,4,5}} http://www.wolframalpha.com/input/?i=rref {{3%2C1%2C3}%2C{5%2C1%2C4}%2C{2%2C4%2C5}}&dataset=

amistre64
 one year ago
Best ResponseYou've already chosen the best response.2firefox doesnt like to copy paste links correctly .. but the wolf agrees with 1/2v1+ 3/2v2
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