A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

Two factory plants are making TV panels. Yesterday, Plant A produced 8000 panels. One percent of the panels from Plant A and 5% of the panels from Plant B were defective. How many panels did Plant B produce, if the overall percentage of defective panels from the two plants was 4% ?

  • This Question is Open
  1. kropot72
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Let x be the total number of panels produced yesterday by plant B. Total production by plant A + plant B = 8000 + x Total defectives made by plant A + plant B = 0.04(8000 + x) Number of defectives made by plant A = 8000 * 0.01 = 80 Number of defectives made by plant B = 0.05x Now we can equate the number of defectives as follows: 0.04(8000 + x) = 80 + 0.05x ...........................(1) Now you need to solve equation (1) to find the value of x, the total number of panels produced yesterday by plant B.

  2. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.