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mathmath333

  • one year ago

Seven different object must be divided among three people .In how many ways can this be done if one or two of them can get no objects ?

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  1. mathmath333
    • one year ago
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    \(\large \color{black}{\begin{align} & \normalsize \text{Seven different object must be divided among three}\hspace{.33em}\\~\\ & \normalsize \text{people .In how many ways can this be done}\hspace{.33em}\\~\\ & \normalsize \text{if one or two of them can get no objects ?}\hspace{.33em}\\~\\ & a.)\ 15120 \hspace{.33em}\\~\\ & b.)\ 2187 \hspace{.33em}\\~\\ & c.)\ 3003 \hspace{.33em}\\~\\ & d.)\ 792 \hspace{.33em}\\~\\ \end{align}}\)

  2. anonymous
    • one year ago
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    dbca

  3. ganeshie8
    • one year ago
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    Seven different objects. Notice that each object has 3 different states, each object can go to one of : {person1, person2, person3} So total possible ways = 3*3*3*3*3*3*3 = 3^7 = 2187

  4. mathmath333
    • one year ago
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    thanks

  5. mathmath333
    • one year ago
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    did this sentence changes any thing "if one or two of them can get no objects"

  6. ganeshie8
    • one year ago
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    yes, that means, one or more can get 0 objects

  7. ganeshie8
    • one year ago
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    obviously all 3 of them cannot get 0 objects because you must give away the 7 objects

  8. ganeshie8
    • one year ago
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    (0, 0, 7) represents the situation : 0 objects to person1 0 objects to person2 7 objects to person3

  9. mathmath333
    • one year ago
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    ok thnks

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