## mathmath333 one year ago Seven different object must be divided among three people .In how many ways can this be done if one or two of them can get no objects ?

1. mathmath333

\large \color{black}{\begin{align} & \normalsize \text{Seven different object must be divided among three}\hspace{.33em}\\~\\ & \normalsize \text{people .In how many ways can this be done}\hspace{.33em}\\~\\ & \normalsize \text{if one or two of them can get no objects ?}\hspace{.33em}\\~\\ & a.)\ 15120 \hspace{.33em}\\~\\ & b.)\ 2187 \hspace{.33em}\\~\\ & c.)\ 3003 \hspace{.33em}\\~\\ & d.)\ 792 \hspace{.33em}\\~\\ \end{align}}

2. anonymous

dbca

3. ganeshie8

Seven different objects. Notice that each object has 3 different states, each object can go to one of : {person1, person2, person3} So total possible ways = 3*3*3*3*3*3*3 = 3^7 = 2187

4. mathmath333

thanks

5. mathmath333

did this sentence changes any thing "if one or two of them can get no objects"

6. ganeshie8

yes, that means, one or more can get 0 objects

7. ganeshie8

obviously all 3 of them cannot get 0 objects because you must give away the 7 objects

8. ganeshie8

(0, 0, 7) represents the situation : 0 objects to person1 0 objects to person2 7 objects to person3

9. mathmath333

ok thnks