What is the average rate of change from x = −2 to x = 0? 1 0 −2 2

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What is the average rate of change from x = −2 to x = 0? 1 0 −2 2

Algebra
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the link isn't working 4me.
ok let mt try this

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okay find y values when x=-2 y =what ? when x=0 y = ?
y=-1?
hmm draw a vertical line at x=-2 ,x=0 |dw:1442576939540:dw|
|dw:1442576947023:dw| at what point red line intersect the graph
at -2
that's x ut you need y
but*
-1 and 1
y values are positive above the x-axis and negative below the x-axis
|dw:1442577127761:dw|
ok so its just 1 then
|dw:1442577166274:dw| when x=-2 y =1
yes right when x =-2 y =1 when x=0 y =1 so now use the slop formula to find slope (average rate of change )\[\huge\rm \frac{ y_2 -y_1}{ x_2-x_1 }\]
so -2
1-1 0-2
or is it 2 cause its 0-(-2)
2nd one looks right
ok thank you for the help
np
wait no
there is 1-1 at the numerator
@Motown117 what did you get for final answer ?
i got 2
no that's not correct
1-1/0-(-2) there is 1-1 at the numerator 1-1 = 0
\[\frac{ 1-1 }{ 0-(-2) }=\frac{ 0 }{ 2 }\] 0 divide by anything equal to what ?
0
yes right so slope is 0
ok thank you
np
can you help me with one more?
i'll try
What is the equation of the quadratic graph with a focus of (4, −3) and a directrix of y = −6? f(x) =negative one over six times x squared plus four over three times x plus eleven over six f(x) =one over six times x squared minus four over three times x minus eleven over six f(x) = three fiftieth x squared plus eleven twenty fifth x plus three fifth f(x) = two fiftieth x squared plus eleven twenty fifth x plus two fifth

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