## anonymous one year ago What is the average rate of change from x = −2 to x = 0? 1 0 −2 2

1. anonymous

@ganeshie8 @Nnesha @nincompoop @pooja195

2. Nnesha

3. anonymous

ok let mt try this

4. anonymous

5. Nnesha

okay find y values when x=-2 y =what ? when x=0 y = ?

6. anonymous

y=-1?

7. Nnesha

hmm draw a vertical line at x=-2 ,x=0 |dw:1442576939540:dw|

8. Nnesha

|dw:1442576947023:dw| at what point red line intersect the graph

9. anonymous

at -2

10. Nnesha

that's x ut you need y

11. Nnesha

but*

12. anonymous

-1 and 1

13. Nnesha

y values are positive above the x-axis and negative below the x-axis

14. Nnesha

|dw:1442577127761:dw|

15. anonymous

ok so its just 1 then

16. Nnesha

|dw:1442577166274:dw| when x=-2 y =1

17. Nnesha

yes right when x =-2 y =1 when x=0 y =1 so now use the slop formula to find slope (average rate of change )$\huge\rm \frac{ y_2 -y_1}{ x_2-x_1 }$

18. anonymous

so -2

19. anonymous

1-1 0-2

20. anonymous

or is it 2 cause its 0-(-2)

21. Nnesha

2nd one looks right

22. anonymous

ok thank you for the help

23. Nnesha

np

24. Nnesha

wait no

25. Nnesha

there is 1-1 at the numerator

26. Nnesha

@Motown117 what did you get for final answer ?

27. anonymous

i got 2

28. Nnesha

no that's not correct

29. Nnesha

1-1/0-(-2) there is 1-1 at the numerator 1-1 = 0

30. Nnesha

$\frac{ 1-1 }{ 0-(-2) }=\frac{ 0 }{ 2 }$ 0 divide by anything equal to what ?

31. anonymous

0

32. Nnesha

yes right so slope is 0

33. anonymous

ok thank you

34. Nnesha

np

35. anonymous

can you help me with one more?

36. Nnesha

i'll try

37. anonymous

What is the equation of the quadratic graph with a focus of (4, −3) and a directrix of y = −6? f(x) =negative one over six times x squared plus four over three times x plus eleven over six f(x) =one over six times x squared minus four over three times x minus eleven over six f(x) = three fiftieth x squared plus eleven twenty fifth x plus three fifth f(x) = two fiftieth x squared plus eleven twenty fifth x plus two fifth