## anonymous one year ago https://i.gyazo.com/8378835c39feec3fec6f647e7cf8b6e2.png help ^

1. anonymous

i think its 16

2. anonymous

because i did 8*2

3. Owlcoffee

Why don't we look at it, from the very proof, let's say we have any two numbers with different exponents: $a^m . a^n$ By definition, they represent a sucession of products so therefore: $\left[ a.a.a.a.a.a.... (m.factors) \right]\left[ a.a.a.a.a...(n.factors) \right]$ a in multiplied "m" times, and also "n" times, so we can deduce that a is multiplied "m+n" times: $\left[ a.a.a.a.a.a....(m+n.factors) \right]$ Therefore, by the very definition of exponent: $a ^{m+n}$ Giving us the conclusion: $a^m. a^n = a ^{m+n}$

4. anonymous

so confused

5. anonymous

but ok o.o

6. Owlcoffee

This means that if you have: $4^2 . 4^8 = 4^{2+8}$ I presume you know what 2+8 is.

7. jameshorton

10