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anonymous
 one year ago
What is the equation of the quadratic graph with a focus of (4, −3) and a directrix of y = −6?
f(x) =negative one over six times x squared plus four over three times x plus eleven over six
f(x) =one over six times x squared minus four over three times x minus eleven over six
f(x) = three fiftieth x squared plus eleven twenty fifth x plus three fifth
f(x) = two fiftieth x squared plus eleven twenty fifth x plus two fifth
anonymous
 one year ago
What is the equation of the quadratic graph with a focus of (4, −3) and a directrix of y = −6? f(x) =negative one over six times x squared plus four over three times x plus eleven over six f(x) =one over six times x squared minus four over three times x minus eleven over six f(x) = three fiftieth x squared plus eleven twenty fifth x plus three fifth f(x) = two fiftieth x squared plus eleven twenty fifth x plus two fifth

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@welshfella @nincompoop @Nnesha @ganeshie8

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1first we should draw a point at (4,3) and horizontal line y=6 dw:1442578792483:dw this one is better

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1442578889393:dw

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1dw:1442578826480:dw yes that's right :=)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1sorry about alright so now we should pick a point to find distance between the point and focus and distance between the point and directrix you can pick any point dw:1442579344198:dw

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1equation would be like this \[\huge\rm \sqrt{(xa)^2+(yb)^2} =\sqrt{ (yc)^2}\] c = directrix (a,b) is a focus point (4,3) now substitute a ,b c for their values

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0square root 4a^2+3b=square root3c^2

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1well (x,y) is a point that we picked we supposed taht (a,b) is the focus point so replace a with 4 b with 3 and c with 6 c is directix

anonymous
 one year ago
Best ResponseYou've already chosen the best response.044^2+3(3)=square root3(6)^2 like this?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1keep the x and y variable \[\large\rm \sqrt{(x4)^2+(y(3))^2} =\sqrt{ (y(6))^2}\] like this now take square both sides to cancel out the square root

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1hmm no (x4)^2 is same as (x4)(x4) foil it signs are the same in the parentheses so you should get 3 terms

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yes right \[x^28x+16+(y(3))^2=(y(6))^2\] foil (y(3))^2 and then right side

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1here is a hint you will get two terms when you have (ab)(a+b) opposite signs

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1hmm no (y(3))^2 first distribute 1(3) ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yes so (y+3)^2 is same as (y+3)(y+3)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yes right \[\large\rm x^28x+16+y^2+6y+9=(y(6))^2\] foil right side

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i dont mean to rush but i have to go soon

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1yes right \[\large\rm x^28x+16+y^2+6y+9=y^2+12y+36\] foil right side now simplify combine like terms

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1well it will takes some time we need to apply the complete the square method .....

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\[\large\rm x^28x+\color{red}{16}+\color{blue}{y^2}+6y+\color{red}{9}=\color{blue}{y^2}+12y+36\] combine like terms at left side and then move y^2 to the right side let me know what you get

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0srry but i have to go thank you any ways

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1okay we will finish this whnevr u hve time

princesssleelee
 one year ago
Best ResponseYou've already chosen the best response.0@Nnesha i have this question as well that i need assistance with.
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