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anonymous
 one year ago
Find the angle between the given vectors to the nearest tenth of a degree.
u = <5, 4>, v = <4, 3>
anonymous
 one year ago
Find the angle between the given vectors to the nearest tenth of a degree. u = <5, 4>, v = <4, 3>

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hi! I can help you! :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you have any ideas about how to get started, or are you completely stuck? :)

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0Hint...dot product \[\large \vec{u} \cdot \vec{v} = uv \cos(\theta)\] So \[\large cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{u v}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@BasketWeave completely stuck :(

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, no problem! John's given you a clue here: we can use the dot product.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you know how to find the dot product between two vectors? :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0u * v = <5,4> , <4,3> =5(4) + 4(3) = 20 + 12 = 32 u = √(5)^2 + (4)^2 =√25 +16 = √41

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0v = √(4)^2 + (3)^2 = √16 + 9 = √25 = 5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0u * v = 32 u =√41 v = 5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 32 }{ \sqrt{41}5} \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well done :) Carry on...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im getting 0.02648....

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now i got, 0.99951.. one of my answer choices is 0.9 degrees, is that correct?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well, try and remember what that 0.99951 means... :) It's not actually the angle!

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.0Right, that leaves us with \[\large cos(\theta) = 0.99951\] What do you get when you actually solve for the angle?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Excellent, well done!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you guys so much for your help!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You're most welcome :)
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