A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Assume that
f(x)={e^x if x≥0, 1+x if x<0
What is lim x→0 f(x), if the limit exist?
Do you understand this? :)
anonymous
 one year ago
Assume that f(x)={e^x if x≥0, 1+x if x<0 What is lim x→0 f(x), if the limit exist? Do you understand this? :)

This Question is Open

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.2Honestly I forgot how to make piecewise functions in latex...so it wont look nice what I do lol..but f(x) = { e^(x), x >= 0 {1 + x, x < 0 Limit as x approaches 0 So...since this doesn't specify if we are going from the left or the right...and just the point where the function breaks into pieces...we need to compute 2 limits limit as x approaches 0 of e^(x) = ??? and limit as x approaches 0 of 1 + x = ??? Once you have those 2 answers: >If they are equal...the limit is THAT answer >If they are different...the limit does not exist

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Here's the latex you're looking for: `\begin{cases}` `e^{x} & \text{for } x\ge0 \\ %optional: [#ex], I use 2 in place of # below` `x+1 & \text{for } x<0` `\end{cases}` \[\begin{cases} e^{x} & \text{for }x\ge0\\[2ex] x+1 & \text{for }x <0 \end{cases}\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.