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anonymous

  • one year ago

In his famous race, a hare runs for a while, takes a nap, and then resumes running until he reaches the finish line. His total displacement from start to finish is 5.0 m east and 12 m north. The hare's total race time, including the time of napping, is 28 minutes. What is the hare's average speed in meters per minute?

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  1. Abhisar
    • one year ago
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    Average speed = Total distance/Total time.

  2. Abhisar
    • one year ago
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    Total distance here will be (5+12)m and total time is given in the question. NOTE:- Even the time he spent while sleeping will be considered.

  3. anonymous
    • one year ago
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    would it be 0.55?

  4. anonymous
    • one year ago
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    @Abhisar

  5. Abhisar
    • one year ago
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    How are you doing?

  6. Abhisar
    • one year ago
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    Average speed = 17/28 meters/min

  7. anonymous
    • one year ago
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    0.607142857143 thats what i got as my answer @Abhisar

  8. Abhisar
    • one year ago
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    That's \(\checkmark\) this time..

  9. anonymous
    • one year ago
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    but they dont have that as an answer choice so i dint know what to choose @Abhisar

  10. anonymous
    • one year ago
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    0.55 m/min 1.2 m/min 0.92 m/min 0.46 m/min This is all they have so would it be 1.2?

  11. Abhisar
    • one year ago
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    All right. this means the rabbit traveled in a straight line. In this case the total distance will be as following|dw:1442588022634:dw|

  12. Abhisar
    • one year ago
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    So the distance is represented by the red line AB. AB= \(\sf \sqrt{5^2+12^2}\) Now, do the same steps, divide the distance with total time.

  13. Abhisar
    • one year ago
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    Getting it?

  14. anonymous
    • one year ago
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    Now i got it thanks man!

  15. Abhisar
    • one year ago
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    You're welcome

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