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anonymous
 one year ago
What is the best way to classify each equation?
Column A Column B
1. 22  3x + 7x = 4(x + 5)
2.6(2x  3) = 3(3x  5)
3.6x  14 = 2(3x  7)
4.6x + 3 (x  4) = 8(x  3)
A.
identity
B.
contradiction
C.
neither
anonymous
 one year ago
What is the best way to classify each equation? Column A Column B 1. 22  3x + 7x = 4(x + 5) 2.6(2x  3) = 3(3x  5) 3.6x  14 = 2(3x  7) 4.6x + 3 (x  4) = 8(x  3) A. identity B. contradiction C. neither

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texaschic101
 one year ago
Best ResponseYou've already chosen the best response.1identity equations are always true no matter what you sub in for the variable...so basically, identity equations have infinite solutions. contradiction equations have no solution. so lets get to work.... 22  3x + 7x = 4(x + 5)  distribute through the parenthesis 22  3x + 7x = 4x + 20  simplify 22 + 4x = 4x + 20  subtract 4x from both sides 22 = 20  incorrect....no solution...contradictory 6(2x  3) = 3(3x  5)  distribute through the parenthesis 12x  18 = 9x  15  subtract 9x from both sides 12x  9x  18 = 15  add 18 to both sides 12x  9x = 15 + 18 3x = 3 x = 1.....this tells me that there is 1 solution....so it is neither 6x  14 = 2(3x  7)  distribute through the parenthesis 6x  14 = 6x  14 0 = 0...correct.....this means there is infinite solutions.... identity 6x + 3(x  4) = 8(x  3)  distribute through the parenthesis 6x + 3x  12 = 8x  24 9x  12 = 8x  24  subtract 8x from both sides 9x  8x  12 = 24  add 12 to both sides 9x  8x = 24 + 12 x =  12....this tells me there is 1 solution...so this one is neither also
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