If a die is rolled twice, what is the probability of rolling a 5 and then a 2?
1
36
B)
1
3
Eliminate
C)
1
6
D)
2
36

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- anonymous

- jamiebookeater

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- anonymous

What is the question.

- texaschic101

I have no idea what this says

- anonymous

Me neither

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- anonymous

OHH. thanks

- anonymous

I meant to type the question too.. Its If a die is rolled twice, what is the probability of rolling a 5 and then a 2?

- MrNood

OK @kkittykat
answer these 3 questions first:
are the 2 instances of rolling the dice independent events?
(that is for YOU to decide)
what is the chance of rolling a 5 with one dice?
what is the chance of rolling a 2 with one dice?

- anonymous

Idk about the independent events and 5 over 6 and 2 over 6 i think

- jameshorton

So, prob. of rolling a 2: 1/6
You want the second roll to be anything but a 2. So that means you have a choice of 5 sides (1,3,4,5,6) and each of these sides has a 1/6 probability of showing up. Therefore the combined probability of rolling any of these five sides = 5*(1/6) = 5/6
Therefore, the probability of rolling a 2 then anything but a 2:
= Prob. of rolling a 2 * Prob. of rolling anything but a 2
= 1/6 * 5/6
= 5/36...Answer

- MrNood

Well you need to decide about independent events
do the results of the first throw influence the results of the second throw?
if NOT then the events are independent
And the probabilities you gave are wrong
there are six possible results on a die - what is the chance of a particular one of those coming up (e.g. a 5?)

- MrNood

@jameshorton
that is not the correct interpretation of the question
you answer is not correct

- MrNood

NO - first - it is against the rules
second you do not 'need to get the maths grade' - you need to know HOW to do it
if oyu did it th esame way a sjames then you did it wrong like James.
answer this first:
there are six possible results on a die - what is the chance of a particular one of those coming up (e.g. a 5?)

- MrNood

going somewhere else for the answer is not 'HELP'
if oyu spend your time at school copying other people's work then you are wasting the best opportunity of your life.
I am prepared to spend as much time HELPING as you need - but no time giving you th eanswer
try to understand the method - then you will have not only the answer to THIS question - but any others like it AND possibly an understanding of chance and odds that may save you a lot of time/money in REAL life.
Eductation is YOUR choice - and it is not about grades it's about understanding

- MrNood

I didn't say 'try again'
I gave you 2 clues:
first
do the results of the first throw influence the results of the second throw?
if NOT then the events are independent
This is something that you may need to think about - but it is key to working out odds like this.
If you throw for instance a 5 with the first throw then you are EQUALLY likely to throw a 5 with th e second throw - i.e. the first does NOT influence the second
The chance of throwing a 5 is the same EVERY time oyu throw a die
so the question is what is that chance?
which is where my second hint comes in:
there are six possible results on a die - what is the chance of a particular one of those coming up (e.g. a 5?)
i.e what is the chance of any ONE out of SIX events happening?

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