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anonymous
 one year ago
@Rushwr
anonymous
 one year ago
@Rushwr

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Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1If the difference in electronegativities between the two atoms is 2.0, or greater, the bond is ionic.

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1Here the electronegativity is 2.34 so it's an ionic bond.

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1But then they have given us the electronegativity table and has asked us to determine the bond type using that right? So I thought she knew about the electronegativity.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The ability for one atom to bind to another?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm sorry I'm horrible at chem my teacher gives me quizes and doesn't explain anything

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1it is the tendency of an atom to attract a bonding pair of electrons

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, so how would I figure this out?

Zale101
 one year ago
Best ResponseYou've already chosen the best response.1OH i read your question wrong I didnt catch the ectronegativity chart @Rushwr i am sorry!

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1they have given us the electronegativity of K and Cl Find the difference if it is greater than 2 they are considered as ionic bonds

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm trying to figure it out now one sec sorry my comp is being slow today

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the difference was 2.34 so it is ionic? @Rushwr

Zale101
 one year ago
Best ResponseYou've already chosen the best response.1Nonpolar covalent has an electronegtivity difference of 0.2  0.5. A polar covalent has an electronegtivity difference less than 1.6. Ionics have an electronegativity greater than 2.0. Yes, 2.34 is greater than 2, so it is ionic.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay what about this one?

Zale101
 one year ago
Best ResponseYou've already chosen the best response.1Lets say this is the periodic tabledw:1442591503283:dw

Zale101
 one year ago
Best ResponseYou've already chosen the best response.1Electrongetivity increases to the right, and upwards of the periodic table

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, one sec I'm pulling one up

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Crap, they're all tiny and I can't see the elements ;;

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Rushwr this is my last one could you help with it...

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1Bubs sorry I was distracted!!! Hold on !

Rushwr
 one year ago
Best ResponseYou've already chosen the best response.1Electronegativity is the ability of an element to pull electron density towards itself, so it causes polarity. Polarity is a difference in the electron density from one end of a molcule/bond to the other. So if you bond something with a high electronegativity to something with a low electronegativity, this big difference causes a partial positive charge on one atom, and a partial negative charge on the other, which is polarity. But similar electronegativities give bonds with little or no polarity.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That kind of helps but I'm still not sure what my answer would be..

diamondboy
 one year ago
Best ResponseYou've already chosen the best response.0@WhatEven..... sorry for coming up late I guess u are good now

diamondboy
 one year ago
Best ResponseYou've already chosen the best response.0what she is trying to say is that when a highly electronegative element bonds with a less electronegative element part of it becomes ve and part +ve, this is polarity. What we need to do now is to find out which one of d options has the highest polarity value

diamondboy
 one year ago
Best ResponseYou've already chosen the best response.0Do u know how to calculate polarity?

diamondboy
 one year ago
Best ResponseYou've already chosen the best response.0ok so all u need to do is to take d value of d highly electronegative element and subtract the less electronegative element from it. An example is this:

diamondboy
 one year ago
Best ResponseYou've already chosen the best response.0dw:1442602097290:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hmmm I'm still kind of confused

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But I lost that question any way can you help with this one?

diamondboy
 one year ago
Best ResponseYou've already chosen the best response.0ok so because F is more electronegative, and hydrogen less electronegative the bond becomes partly ve and partly +ve. The highly electronegative one has the ve charge while the less electronegative one has the positive charge

diamondboy
 one year ago
Best ResponseYou've already chosen the best response.0ve means negative and +ve means positive

diamondboy
 one year ago
Best ResponseYou've already chosen the best response.0the answer to ur question is between option C and D

diamondboy
 one year ago
Best ResponseYou've already chosen the best response.0do u know ur answer now?

diamondboy
 one year ago
Best ResponseYou've already chosen the best response.0Fluorine is more electronegative and so it should have the ve charge

diamondboy
 one year ago
Best ResponseYou've already chosen the best response.0hows dat? did it work?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And this is my last one but I have to leave or I'll be late getting my friends brother can you tell me and when I'm back on explain why? and it was right

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks I'll be back in like 45 minutes or less
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