(6^2)^x = 1, what is the value of x? Explain your answer!

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(6^2)^x = 1, what is the value of x? Explain your answer!

Mathematics
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@madhu.mukherjee.946

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Other answers:

hint a^0 = 1
and (a^x)^y = a^{xy}
Can you explain this to me step by step i don't get this. plz
anyone?
x = 0 because anything raised rto the 0 power is 1
6^2=36 so 36 ^0 =1
Can you also help me with this one plz? this is part B.
this is an indices property that anything raised to the power is 0
If (60)x = 1, what are the possible values of x? Explain your answer.
60x=1 x=1/60
this 60 multiplied to x and that was 36^x
Assuming you mean 60^x=1, that's exactly the same question.
is it 60^x 0r 60 x
It is not the same question how do i do part B?
what is part b?
60x=1 x=1/60
a. (6^2)^x = 1 b. 60^x = 1 These are the same problem with a different number in parentheses. If anything raised to the \(0\) power is 1, what does x have to be?
So is both Part A and Part B have the same answer?
yes.
nope
part is (60)x=1 x=1/60
there can not be such answers in exponents or can there?
@Spring98 yes there can be. that's called a rational exponent, my guess is you'll get there shortly. You should use 60^x to indicate exponents @madhu.mukherjee.946 was asking you to clarify the question above.
60x = 1 is different from 60^x = 1
thats what i'm saying
sdo both the answers are 1 then right?
@peachpi @madhu.mukherjee.946
The right side of all these equations are 1. The exponents are all 0. What are you looking for in your questions, the exponent or the right side?|dw:1442594854616:dw|
what is Part B answer????
I don't give answers. You've gotten 3 explanations for this problem. What are you confused about?
i can't find the solution
|dw:1442595279818:dw|
so what does x have to be?
0?
yes!!!
wait but both the answers are going to be 0 right?
yeah
yes, that's what they're trying to get you to learn. It doesn't matter what the base is. Anything to the 0 is 1
Thanks Both of you!!

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