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anonymous
 one year ago
Pleasse helppp
1.Stacy reads that a 50:50 mixture of methanol and water is best for keeping a car’s radiator from freezing when the temperature goes down to –40°C. Design an experiment to test this finding. You have a –40°C freezer, water, methanol, graduated cylinders to measure volume, several plastic beakers, and a watch at your disposal. Be sure to state your hypothesis, procedure, and any controls in your experiment. What are the dependent and independent variables? Explain the possible results if your hypothesis is true.
(Note: Car antifreeze is a mixture of water and another substance
anonymous
 one year ago
Pleasse helppp 1.Stacy reads that a 50:50 mixture of methanol and water is best for keeping a car’s radiator from freezing when the temperature goes down to –40°C. Design an experiment to test this finding. You have a –40°C freezer, water, methanol, graduated cylinders to measure volume, several plastic beakers, and a watch at your disposal. Be sure to state your hypothesis, procedure, and any controls in your experiment. What are the dependent and independent variables? Explain the possible results if your hypothesis is true. (Note: Car antifreeze is a mixture of water and another substance

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.02. You have 2 m3 of a mineral ore sample. It has a mass of 1 × 104 kg. Calculate the density of the ore sample and express your results in g/cm3 with appropriate scientific notation. Answer:

anonymous
 one year ago
Best ResponseYou've already chosen the best response.01. The data in the table below represent the pressure of a gas when you change the temperature. Plot a graph of the data, using the blank graph provided below. Draw a trend line and calculate its slope. Are the variables related in any way? If so, explain how. What will be the pressure of the gas at 0°C?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hi: what do you need help in?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0about the first question how do you plan to test if the hypothesis is correct?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What is your hypothesis?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know a hypothesis is an If and then statement

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Im confused in the question itself. :(

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok in this case what is the question that Stacy want to answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if methanol and water is best for keeping a car’s radiator from freezing when the temperature goes down to –40°C?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes! also she has a 50:50 mixture that she think is the best. then whit this information you can write the hypothesis

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you dont need to use the if, just write a sentence with this information

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If a Methanol and Water is mixed at a 50:50 Ratio, then the mixture will keep the radiator from freezing when the temperature goes down to –40°C?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thats looks pretty good. That can be your hypothesis. Now you have to think in experiments to prove o disprove that sentence

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok . The hard part lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you have freezer, water, methanol, graduated cylinders to measure volume, several plastic beakers, and a watch at your disposal. What can you do?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Put Water in one beaker and methanol in the other.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Im lost from there :(

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Good! that can be your controls, then you can made a 50:50 mix water and alcohol too (that will be the mix that you want to test)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok so im confused about the volume thing

anonymous
 one year ago
Best ResponseYou've already chosen the best response.050:50 is a mix that have the same amount of water and alcohol. per example: 10mL water + 10 mL alcohol = 20 mL of mix or any other volume but both the same

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh ok i get it, but what about the watch. And what would be my independent and dependents

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok we can organize what we have, we have 3 plastic beakers, one with 20mL of water, other with 20 mL of alcohol, and other with 20 mL of the mix. All of them at room temperature. Now we can put them in the freezer and wait a time, p.e.: 10 min and open the freezer and see what happen with the liquids in the 3 containers We can put them back and wait other 10 min or longer times.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Independent variable are the one that you fix in the experiment and dependent variables are the ones that result from the measurement of the results depending of the independent variable that you fixed. Do you understand?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the variables that you have are: the amount of water in the mix or in your controls the amount of alcohol in the mix or in your controls the time to take the mix to freeze

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the temperature of the freezer is not a variable because you will keep the same all the experiment so that is going to be a constant

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Omg Thank you soo much. Chem is so challenging for me

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can you please please please hep me with thye other two Im soo confused

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0did you figure out which ones are the dependent and the independent variables?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what will be the results if your hypothesis is true?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Independent: The amount of water in the mix, the amount of alcohol in the mix Dependent: The time to take the mix to freeze Consent: The temperature of the freezer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The result is that the Mixture of Methanol and Water can keep a car’s radiator from freezing when the temperature goes down to –40°C.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The result is that the Mixture of Methanol and Water can keep a car’s radiator from freezing when the temperature goes down to –40°C. Because while the beaker with water and the beaker with methanol froze, the one that was mixed did not freeze.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The beaker with methanol may not freeze at 40C, the melting point of the methanol is 97C. But if you use methanol in the radiator will boil at 64C much lower than water(100C), when you have the mix the boiling and freezing points will change

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you..!! Can you please help with the other two?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.02. You have 2 m3 of a mineral ore sample. It has a mass of 1 × 104 kg. Calculate the density of the ore sample and express your results in g/cm3 with appropriate scientific notation.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok Density = mass/ volume so bassicaly you have to do a division of the mass by the volume. The difficulty in the problem is that the mass is given in kg and the volume in m3 and the answer has to be in g/cm3 so you have to convert the kg > g and the m3 > cm3 are you familiar with unit conversions and conversion factors?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.01 kg = 100g 1m3 = 1 x 10^6 cm3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok im sorry, im back

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm familiar with Unit conversion but not factor

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok convert the kg > g and the m3 > cm3 and do the division mass/volume

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0mass = 1*10^7 grams volume = 2*10^6 cm^3 divide mass/volume

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But can you express your results in g/cm3 with appropriate scientific notation for me cause thats the hard part

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0in this case is very simple the answer is just 5 g/cm3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How to express it in scientific notation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.01. The data in the table below represent the pressure of a gas when you change the temperature. Plot a graph of the data, using the blank graph provided below. Draw a trend line and calculate its slope. Are the variables related in any way? If so, explain how. What will be the pressure of the gas at 0°C? find the intersection of the values and mark a dot in the paper 10C 723 torr, then the next one 25C 763 torr and so on

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that number has only one digit and you dont need to express in scientific notation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sorry for taking so long:( toke me a while to find how to even find a way to put dots and lines on the graph lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then divide pressure over volume P/V for each point and calculate the average value. Or you can calculate from the graph. The value has to be similar. To calculate the pressure at 0C just look at the value in the graph where the line cut the pressure axis

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok i dont get the P/V thing. Wheres the volume?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok Give me a sec to do that calculations:)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sorry you have to do a delta choose two temperature and two pressures and do the difference between them, then do the division of P/T to calculate the slope of the line

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hold On.... Major Brain Crash. Im confused now

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0choose two temperatures

anonymous
 one year ago
Best ResponseYou've already chosen the best response.055/845=15.36 80/900=11.25

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hold on wait i divided them

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok, what you have to do is the difference between the two pressures divided the difference of the two temperatures

anonymous
 one year ago
Best ResponseYou've already chosen the best response.055845=790 80900=820

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No, (900845)/(8055)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(900845)/(8055) 55/25=2.2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes you can watch this video if you want to know better how to calculate the slope of a line from the graph https://www.khanacademy.org/math/cceighthgrademath/cc8thlinearequationsfunctions/8thslope/v/slopeofaline

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so 2.2 would be the slop

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Or would i have to do that to all of them

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0since this is a straight line any two point will give a similar answer. You can do for all the points and calculate the average if you want o do the job. Or also it can be calculate from the graph

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you so much!!!!!!! You helped me to the max! Can I ask one more question or are you tired of me lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Also am i able to give you owl bucks on here?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you for the testimonial. I dont have idea about the owl buck I think I have to be a qualified Help and I am not yet.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok Would you like if i close this question then ask another so it can add to your stats?
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