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anonymous
 one year ago
Use "Lagranges" multiplication method to find points in the curve; 5x^2 + 6xy + 5y^2 = 1, which is closest and furtherest away from origo  and find the max/min distance.
What would be the steps involved solving this?
anonymous
 one year ago
Use "Lagranges" multiplication method to find points in the curve; 5x^2 + 6xy + 5y^2 = 1, which is closest and furtherest away from origo  and find the max/min distance. What would be the steps involved solving this?

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IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0you are minimising a function  the distance formula  which we shall call f(x,y) with this ellipse as the condition g(x,y) the lagrange multiplier reduces the algebra down to solving this: \(\nabla f = \lambda \nabla g\) ie solve for \(\lambda\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay, It looks like I will have to do some more work on gradients  as I am not very familiar with those

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0well, that's just shorthand for \(\large \frac{\partial f}{\partial x} = \lambda\frac{\partial g}{\partial x}\) and \(\large \frac{\partial f}{\partial y} = \lambda\frac{\partial g}{\partial y}\)
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