the solutions to the inequalities 0 ≤ x ≤ 2, 0 ≤ y ≤ 1, and y ≤ -(1/2x) + (3/2) form a polygonal region in the plane. How many sides does this polygon have?

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the solutions to the inequalities 0 ≤ x ≤ 2, 0 ≤ y ≤ 1, and y ≤ -(1/2x) + (3/2) form a polygonal region in the plane. How many sides does this polygon have?

Mathematics
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Hi ... I can help you with this. Let's take each piece separately. Do you know what the graph of \[0 \le x \le 2\] looks like?
(You could use the "Draw" button to draw it...)
Hint: you want all the points \[(x,y)\] that have x-values between 0 and 2.

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I'm new here ... is there any way of knowing if someone is still there wanting help with a question, or if they've left?
i do not see the draw button. And yes i do need help please.
Sorry -- I thought you were gone. Are you still here? Do you still want help with this?

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