anonymous
  • anonymous
f(x)=4x+3 helpp
Mathematics
jamiebookeater
  • jamiebookeater
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whovianchick
  • whovianchick
What are we helping to do?
anonymous
  • anonymous
figure out f(x)=4x+3
anonymous
  • anonymous
can you walk me through it

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whovianchick
  • whovianchick
What do you mean figure it out? What are the instructions on the problem?
anonymous
  • anonymous
how do you do it
anonymous
  • anonymous
f(x) = 4x + 3 is a statement, not a question. What are you trying to do with the function?
anonymous
  • anonymous
get like an answer at the end what would i tell my teacher
anonymous
  • anonymous
what were you asked? there has to be some instructions
anonymous
  • anonymous
evaluate it
Vocaloid
  • Vocaloid
did they give you any other information?
Vocaloid
  • Vocaloid
like, did they give you an x value?
anonymous
  • anonymous
ok, now we're getting somewhere. Are you supposed to evaluate it at a specific value of x?
anonymous
  • anonymous
lets say x is 2
anonymous
  • anonymous
ok, so you would substitute 2 for x f(x) = 4x + 3 f(2) = 4(2) + 3 then simplify that
whovianchick
  • whovianchick
Don't multiply f and 2 though, that's basically y. It stays f(2), or function of 2.
anonymous
  • anonymous
ok
anonymous
  • anonymous
11
anonymous
  • anonymous
yep
anonymous
  • anonymous
can i ask a couple more
anonymous
  • anonymous
ok
anonymous
  • anonymous
f(x)=2x+4 G(x)=X+1
anonymous
  • anonymous
no actually
anonymous
  • anonymous
f(x)=5x+3 G(x)=x+4
anonymous
  • anonymous
ok what are the instructions for this one?
anonymous
  • anonymous
i have to combine them but I'm confused
anonymous
  • anonymous
ok, there are lots of different ways to combine functions. It really depends on what you're asked for. Do you have a specific combination, or do you just want me to show you some
anonymous
  • anonymous
can you show me some
anonymous
  • anonymous
ok let's start with the basic 4 Adding \(f(x) + g(x) = 5x + 3 + x + 4\) \(= 6x + 7\) Subtracting \(f(x) - g(x) = 5x + 3 - (x + 4)\) \(=5x+3-x-4\) \(=4x-1\) \(g(x) - f(x) = x + 4-(5x+3)\) \(=x+4-5x-3\) =\(-4x+1\) Multiplying \(f(x)\cdot g(x)=(5x+3)(x+4)\) \(=5x^2+20x+3x+12\) \(=5x^2+23x+12\) Dividing \[\frac{ f(x) }{ g(x) }=\frac{ 5x+3 }{ x+4 }\] \[\frac{ g(x) }{ f(x) }=\frac{ x+4 }{ 5x+3 }\]
anonymous
  • anonymous
Then you can get more complex with something like \(2f(x)-3g(x)=2(5x+3)-3(x+4)\) =\(10x+6-3x-12\) =\(7x-6\)
anonymous
  • anonymous
You can also compose functions, which is basically putting one inside the other. To find f(g(x)) replace the x in f(x) with the function from g(x). \(f(g(x))=5(x+4)+3\) \(=5x+20+3\) \(=5x+23\) To find g(f(x)), do the opposite and replace the x in g(x) with f(x) \(g(f(x))=(5x+3)+4\) \(=5x+7\)
anonymous
  • anonymous
ok can you walk me through on Subtracting f(x)−g(x)=5x+3−(x+4) =5x+3−x−4 =4x−1 g(x)−f(x)=x+4−(5x+3) =x+4−5x−3 =−4x+1 how'd you get that
anonymous
  • anonymous
from the first line to the second you have to distribute. -(x + 4) = -x - 4 for the first one and -(5x + 3) = -5x - 3 then you combine like terms Is that what you meant?
anonymous
  • anonymous
yea thank you and what about the others sorry I'm asking so much its just that i need to pass this
anonymous
  • anonymous
no problem. for multiplying you usually have to use FOIL or do some distribution. dividing is just writing one on top of the other like a fraction
anonymous
  • anonymous
ok
anonymous
  • anonymous
Most of this is really knowing how to apply the distributive property and combine like terms
anonymous
  • anonymous
ok thank you
anonymous
  • anonymous
you're welcome

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