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anonymous
 one year ago
If a, b and c are odd integers, which of the following expressions must be an even integer?
a + b + c
a(b + c)
ab + bc + ca
a(b + c  1)
anonymous
 one year ago
If a, b and c are odd integers, which of the following expressions must be an even integer? a + b + c a(b + c) ab + bc + ca a(b + c  1)

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whovianchick
 one year ago
Best ResponseYou've already chosen the best response.3No, it's B. plug in odd numbers for all of the variables, and you get B every time

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0First fact needed: ODD + ODD = EVEN This is always true. And, ODD + EVEN = ODD. So, a + b + c is (ODD + ODD + ODD) = (ODD + ODD) + ODD = EVEN + ODD = ODD.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Now, we need more facts. (EVEN)(EVEN) = EVEN and (EVEN)(ODD) = EVEN; that is, multiplying by an even number always given you an even number. Do you see how that can help you with a(b + c)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'll get you started: ODD(ODD + ODD) = ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0RIght... ODD(ODD + ODD) = ODD(EVEN) = EVEN. Yep!

whovianchick
 one year ago
Best ResponseYou've already chosen the best response.3It's B, I've already answered. Plug in numbers, and you'll see I'm right

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Now, how about the others? (Perhaps there is more than one that must always be even...)

KaylaRdz0405
 one year ago
Best ResponseYou've already chosen the best response.0i agree with whovianchick

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Plugging in #s is a good approach. Sometimes it's useful to use some other ideas, too.

whovianchick
 one year ago
Best ResponseYou've already chosen the best response.3@OneMathCat The problem is already solved. Stop rambling.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yep!! I do have a tendency to ramble ... sorry! Have a good day!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0THANK U @whovianchick
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