At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
i think c
No, it's B. plug in odd numbers for all of the variables, and you get B every time
First fact needed: ODD + ODD = EVEN This is always true. And, ODD + EVEN = ODD. So, a + b + c is (ODD + ODD + ODD) = (ODD + ODD) + ODD = EVEN + ODD = ODD.
Now, we need more facts. (EVEN)(EVEN) = EVEN and (EVEN)(ODD) = EVEN; that is, multiplying by an even number always given you an even number. Do you see how that can help you with a(b + c)?
I'll get you started: ODD(ODD + ODD) = ?
RIght... ODD(ODD + ODD) = ODD(EVEN) = EVEN. Yep!
It's B, I've already answered. Plug in numbers, and you'll see I'm right
Now, how about the others? (Perhaps there is more than one that must always be even...)
i agree with whovianchick
Plugging in #s is a good approach. Sometimes it's useful to use some other ideas, too.
@OneMathCat The problem is already solved. Stop rambling.
Yep!! I do have a tendency to ramble ... sorry! Have a good day!
THANK U @whovianchick
no prob :)