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LifeIsADangerousGame
 one year ago
Calculus
LifeIsADangerousGame
 one year ago
Calculus

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LifeIsADangerousGame
 one year ago
Best ResponseYou've already chosen the best response.0\[\lim_{x \rightarrow 2} \frac{ \left x  2 \right }{ x  2 }\]

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2the limit will be different for x approaching 2 from above and that for x approaching 2 from below. Because the numerator will always be positive ( absolute value)

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2Limits are not my strong point I'm afraid

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2My guess is that the limit is 1 for x approaching above 2 , and 1 for x approaching from below 2. But i'm not sure.

LifeIsADangerousGame
 one year ago
Best ResponseYou've already chosen the best response.0That's what the calculator I used says, I just don't know how to show my work for it.

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1May not be your strong point, however you are correct @welshfella :) As you said, the limit = 1 as we approach 2 from the left And the limit = 1 as we approach 2 from the right Since there are 2 different values, the limit does not exist

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2Right  i cant help you there.

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Its easy to show, Instead of putting in 2 for 'x' Plug in 1.99999 for 'x' to show what the answer would be if we approach 2 from JUST below it And plug in 2.00001 for 'x' to show what it would be if we approach 2 from JUST above it

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2 yes  I had something like that in my mind also.

LifeIsADangerousGame
 one year ago
Best ResponseYou've already chosen the best response.0Thank you both!
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