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LifeIsADangerousGame
 one year ago
I already know the answer, but the way I did it is wrong I think.
LifeIsADangerousGame
 one year ago
I already know the answer, but the way I did it is wrong I think.

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LifeIsADangerousGame
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ \sqrt{x}  3 }{ 9  x }\]

LifeIsADangerousGame
 one year ago
Best ResponseYou've already chosen the best response.0I multiplied by the conjugate which gave me \[\frac{ x  9 }{ (9  x)(\sqrt{x} + 3) }\]

LifeIsADangerousGame
 one year ago
Best ResponseYou've already chosen the best response.0(the answer is 1/6 btw) I want to cancel out x  9, but what I did was switch (x  9) into 9 + x and then multiply the denom by 1, but I don't think that's right.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0actually that is right

LifeIsADangerousGame
 one year ago
Best ResponseYou've already chosen the best response.0It is? You can multiply the denom by negative one and not the numerator too?

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Well you're not really just multiplying the denominator... \[\large \frac{\sqrt{x}  3}{9x} \times \frac{\sqrt{x} + 3}{\sqrt{x} + 3} = \frac{x  9}{(9  x)(\sqrt{x} + 3)}\] As you said you can rewrite \(\large (9  x)\) as \(\large (x + 9)\) So \[\large \frac{x9}{(x + 9)(\sqrt{x} + 3)}\] Now, if you factor out a 1...what do you get? \[\large  \frac{\cancel{x + 9}}{(\cancel{x + 9})(\sqrt{x} + 3)} = \frac{1}{\sqrt{x} + 3 }\]

LifeIsADangerousGame
 one year ago
Best ResponseYou've already chosen the best response.0Oh I see, I think

LifeIsADangerousGame
 one year ago
Best ResponseYou've already chosen the best response.0Does that look about right? It's an awkward way of showing your work, but it's the only way I can submit it
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