A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
Verify that y=tan(x+c) is a one parameter family of solutions of the differential equation y'=1+y^2
anonymous
 one year ago
Verify that y=tan(x+c) is a one parameter family of solutions of the differential equation y'=1+y^2

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0y=tan(x+c) y'=sec^2(x+c)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Answer: No real solutions.

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1keep going @Mateaus

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0y'=sec^2(x+c) y'=tan^2(x+c)+1 that's how far I can simplify it but I am unsure if there is a possible way to get y'=1+y^2

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1?? you have done it, you were given : y'=1+y^2 with: y=tan(x+c) you showed that : y'=sec^2(x+c) [= y^2 +1]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh! derp... I see. Did the same mistake for another problem lol
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.