anonymous
  • anonymous
Give and example ( by writing an equation) of each of the following: a function whose domain is [0, infinity) a function whose domain is ( -infinity, infinity) a function whose domain is (-infinity, 0) u ( 0, infinity)
Mathematics
  • Stacey Warren - Expert brainly.com
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katieb
  • katieb
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anonymous
  • anonymous
help
anonymous
  • anonymous
@sweetburger @Gemini_Nation_ @Firez @fishes220 help someone
anonymous
  • anonymous
help

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anonymous
  • anonymous
@IrishBoy123 some one help i give medals!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
anonymous
  • anonymous
ill help
anonymous
  • anonymous
thanks
anonymous
  • anonymous
one sec
anonymous
  • anonymous
k
anonymous
  • anonymous
f(x) = x + 1 for number 2
anonymous
  • anonymous
f(x) = x + 1 for number 2
anonymous
  • anonymous
1-x if x is greater than or equal to zero. third 1
anonymous
  • anonymous
and finally the first 1 is f(x)= x +4 if x is less than zero
anonymous
  • anonymous
did this help @Julianne6th
anonymous
  • anonymous
yes
anonymous
  • anonymous
is this right
anonymous
  • anonymous
You can't take the square root of negative numbers, so the domain of \[f(x) = \sqrt x\] is: \[[0,\infty)\]
anonymous
  • anonymous
What is the domain of this function: \[f(x) = 1/x\] (Think: what number(s) are you not allowed to plug in for x?)
anonymous
  • anonymous
this is @cookiimonster627 question i posted it for him or her
anonymous
  • anonymous
just FYI: the domains of both f(x) = 1-x and f(x) = x + 4 are all real numbers: that is, the interval (-infinity,infinity). Why? What number(s) can be plugged into 1 - x ? Any numbers! That is, you can subtract *any* number from 1. (and so on)
anonymous
  • anonymous
@OneMathCat your so wrong that shows your not a math cat

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