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anonymous

  • one year ago

Give and example ( by writing an equation) of each of the following: a function whose domain is [0, infinity) a function whose domain is ( -infinity, infinity) a function whose domain is (-infinity, 0) u ( 0, infinity)

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  1. anonymous
    • one year ago
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    help

  2. anonymous
    • one year ago
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    @sweetburger @Gemini_Nation_ @Firez @fishes220 help someone

  3. anonymous
    • one year ago
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    help

  4. anonymous
    • one year ago
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    @IrishBoy123 some one help i give medals!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

  5. anonymous
    • one year ago
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    ill help

  6. anonymous
    • one year ago
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    thanks

  7. anonymous
    • one year ago
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    one sec

  8. anonymous
    • one year ago
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    k

  9. anonymous
    • one year ago
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    f(x) = x + 1 for number 2

  10. anonymous
    • one year ago
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    f(x) = x + 1 for number 2

  11. anonymous
    • one year ago
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    1-x if x is greater than or equal to zero. third 1

  12. anonymous
    • one year ago
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    and finally the first 1 is f(x)= x +4 if x is less than zero

  13. anonymous
    • one year ago
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    did this help @Julianne6th

  14. anonymous
    • one year ago
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    yes

  15. anonymous
    • one year ago
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    is this right

  16. anonymous
    • one year ago
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    You can't take the square root of negative numbers, so the domain of \[f(x) = \sqrt x\] is: \[[0,\infty)\]

  17. anonymous
    • one year ago
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    What is the domain of this function: \[f(x) = 1/x\] (Think: what number(s) are you not allowed to plug in for x?)

  18. anonymous
    • one year ago
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    this is @cookiimonster627 question i posted it for him or her

  19. anonymous
    • one year ago
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    just FYI: the domains of both f(x) = 1-x and f(x) = x + 4 are all real numbers: that is, the interval (-infinity,infinity). Why? What number(s) can be plugged into 1 - x ? Any numbers! That is, you can subtract *any* number from 1. (and so on)

  20. anonymous
    • one year ago
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    @OneMathCat your so wrong that shows your not a math cat

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