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anonymous

  • one year ago

URGENT! HELP PLEASE, I'LL REWARD YOU solve f(x) =x^2-4x+3 show work

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  1. anonymous
    • one year ago
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    @mathmate

  2. anonymous
    • one year ago
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    @mathlover2014

  3. LifeIsADangerousGame
    • one year ago
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    Solve for x?

  4. anonymous
    • one year ago
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    for f(-2)

  5. anonymous
    • one year ago
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    @LifeIsADangerousGame

  6. LifeIsADangerousGame
    • one year ago
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    Oh, okay. So when it says solve for f(x) = x^2-4x+3 when f(-2) it means plug in -2 for x in the equation. So: f(-2) = -2^2 - 4(-2) + 3 =

  7. anonymous
    • one year ago
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    im so confused. i was taught to substitute f(x) with y

  8. anonymous
    • one year ago
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    can you help me please and show the work? cause i know after that i have to switch out the variables

  9. anonymous
    • one year ago
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    and i have to turn this in within the next 5 minutes

  10. Bossvideogamer21
    • one year ago
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    i will help too

  11. anonymous
    • one year ago
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    thank you!

  12. LifeIsADangerousGame
    • one year ago
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    Okay: f(x) = x^2-4x+3 f(-2) = (-2)^2-4(-2)+3 f(-2) = 4 + 8 + 3 f(-2) = 15

  13. Bossvideogamer21
    • one year ago
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    what does the sign right next to the x mean

  14. LifeIsADangerousGame
    • one year ago
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    Where at?

  15. Bossvideogamer21
    • one year ago
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    in the question it says x^

  16. Bossvideogamer21
    • one year ago
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    so what does this ^ mean?

  17. LifeIsADangerousGame
    • one year ago
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    f(x) IS y, but in this case you would not put -2 for y because this is not that type of problem. ^ means exponent. So x^2 is the same as \[x ^{2}\]

  18. anonymous
    • one year ago
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    |dw:1442608024278:dw|

  19. Bossvideogamer21
    • one year ago
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    oh thank u

  20. anonymous
    • one year ago
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    NP

  21. LifeIsADangerousGame
    • one year ago
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    Pro tip: Often times, when you plug in -2^2 or something similar into a calculator, the calculator will read it is -(2^2) and will give you the wrong answer. To prevent this, plug in (-2)^2, this forces the calculator to realize you are squaring a negative number.

  22. Bossvideogamer21
    • one year ago
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    here is the real answer:

  23. Bossvideogamer21
    • one year ago
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    ax^2+bx+c x^2-4x+3 (x-3)(x-1)=0 x=3, x=1 when y=0 The graph of the parabola has a minimum because a is positive. (3+1)/2=2 so y will be at a minimum when x=2 f(x)=y=2^2-(4*2)+3 =4-8+3

  24. Bossvideogamer21
    • one year ago
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    may i have my reward now?

  25. Bossvideogamer21
    • one year ago
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    after all i did answer ur question

  26. mathmate
    • one year ago
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    @rosamartinez "solve" and "evaluate/calculate" have different meanings in mathematics. For your information, to "solve" means to find the unknown given and equation, for example, solve 5x+3=18, then we "solve" by isolating x on the left, and find that x=3. When we are given all information to calculate the value of a function, we say "evaluate" f(-2), since x=-2, and the function is given/defined. For the given case, we can "solve" f(x)=x^2-4x+3=0 (if =0 was given) in which case f(x)=(x-3)(x-1)=0, or x=3 or x=1. or "evaluate" f(-3), then f(-3)=(-3)^2-4(-3)+3=9+12+3=24.

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