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anonymous

  • one year ago

How would I go about finding x and y? |x| + |y| = |x + y|

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  1. anonymous
    • one year ago
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    i think you make your own example like 5+3=8

  2. welshfella
    • one year ago
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    there are infinite solutions for example |1! + |2| = |1 + 2| and many ,many more

  3. anonymous
    • one year ago
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    I think the thing that I am more confused with is what would x and y have to be (such as negative or positive) that would be right, sorry I didn't explain the question correctly I mean for |x| + |y| < |x+y| xD

  4. zzr0ck3r
    • one year ago
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    This is always true, just to let you know...it may help \[|a+b|\le |a|+|b|\]

  5. anonymous
    • one year ago
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    What you have is less than or equal to. I am thinking more of just less than, and switched around

  6. zzr0ck3r
    • one year ago
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    you will never find \(|a|+|b|<|a+b|\)

  7. anonymous
    • one year ago
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    Interesting, How would you interpret the word problem: "Write the statement where the sum of the absolute values of two numbers is less than the absolute value of the sum of the two numbers."

  8. welshfella
    • one year ago
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    you interpreted it correctly

  9. anonymous
    • one year ago
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    So that would interpret to |x|+|y|<|x+y|? and if so, there must be some value for x and y that would make the equation true, correct?

  10. zzr0ck3r
    • one year ago
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    There is not. \[a^2+b^2+2|a||b|\ge a^2+b^2+2ab\] Now \(|a|^2=a^2\) for any number \(a\). So from above \[|a|^2+|b|^2\ge |a+b|^2\implies |a|+|b|\ge |a+b|\]

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